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murzikaleks [220]
2 years ago
8

PLEASE HELP

Mathematics
1 answer:
Leviafan [203]2 years ago
4 0

Answer:

An artist use 51.9 feet of string for constructing a piece of art in the shape of rectangle

Step-by-step explanation:

Here an artist is constructing a piece of art in the shape of rectangle having length 12 feet & width of 7 feet

Since the artist wants to use string to tightly tie each vertex of rectangle to the other three vertices. Hence one string will tie in a diagonal way

Hence total length of string will be

Total length = Perimeter of rectangle  +  length of diagonal

Perimeter of rectangle  = 2( length + width ) = 2 ( 12 + 7 ) = 2 x 19 = 38 feet

Length of diagonal given by Pythagoras theorem

\mathrm{Length =   {  \left(  { a  }^{ 2  }  + { b  }^{ 2  }    \right)    }^{ 0.5  }     =    {  \left(  { 12  }^{ 2  }  + { 7  }^{ 2  }    \right)    }^{ 0.5  }     = 13.89244\:\:feet}

Hence

Total length = Perimeter of rectangle  + length of diagonal

Total length = 38 feet + 13.89244 feet = 51.9 feet

Hence an artist use 51.9 feet of string for constructing a piece of art in the shape of rectangle

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Answer:

x = log 10/log 3

Step-by-step explanation:

3^x - 4 = 6

3^x = 10

We take log base 3 of both sides since log_3 3^x is simply x.

log_3 3^x = log_3 10

x = log_3 10

We have an answer for x, but it is a log base 3. We want log base 10.

Now we use the change of base formula.

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3 years ago
Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i
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Answer:

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2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then


17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},

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12t=\log_{1.0054}3,

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3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.

The best will be 2nd option, because $8032.58>$7936.39

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