Answer:
As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.
Explanation:
Absorbance of light by a reagent of concentration c, is given as
A = εcl
A = Absorbance
ε = molar absorptivity
c = concentration of reagent.
l = length of light path or length of the solution the light passes through.
So, if all.other factors are held constant, If a sample for spectrophotometric analysis is placed in a 10-cm cell, the absorbance will be 10 times greater than the absorbance in a 1-cm cell.
But the reagent blank solution is called a blank solution because it lacks the given reagent. A blank solution does not contain detectable amounts of the reagent under consideration. That is, the concentration of reagent in the blank solution is 0.
Hence, the Absorbance is subsequently 0. And increasing or decreasing the path length of light will not change anything. As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.
Hope this Helps!!!
Answer:
Explanation:
Manganese is the element of group 7 and forth period. The atomic number of Manganese is 25 and the symbol of the element is Mn.
The electronic configuration of the element, manganese is -
To form 
, it will lose 3 electrons from the valence electrons and thus the configuration of the ion is:-
5e earth holds many answers to things we don’t know about.
Answer: D. like dissolves like
Explanation:
The solubility of substances is governed by: Like dissolves like, which states that polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar solvents.
Hydrocarbons are non polar in nature due to less difference between the electronegativities of carbon and hydrogen and thus are soluble in non polar solvents only.
Ionic compounds which are formed by elements with high electronegativity difference are polar in nature and thus dissolve in polar solvents.
Example: 
in water.
Answer:
V₂ = 1473.03 L
Explanation:
Given data:
Initial volume = 980 L
Initial pressure = 107.2 atm
Initial temperature = 71 °C (71 +273.15 = 344.15 K)
Final temperature = 13°C (13+273.15 = 286.15K)
Final volume = ?
Final pressure = 59.3 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K× 59.3 atm
V₂ = 30061774.4 atm .L. K / 20408.095 atm. K
V₂ = 1473.03 L
