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faust18 [17]
3 years ago
5

How many liters of oxygen (at STP) are required to form 10.5 grams of hydrogen

Chemistry
1 answer:
Bond [772]3 years ago
8 0

Answer:

You'd need 6.55 L of oxygen at STP to form that much water.

Explanation:

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True or False: With a given number of moles of solvent, the solution will always have the same concentration
ycow [4]
It’s true!!!!!!!!! Hope you do great in your test
7 0
3 years ago
Read 2 more answers
A sample of an unknown substance has a mass of .158 kg if 2,510 J of heat is required to heat the substance from 32°C to 61°C wh
ziro4ka [17]

Answer: 0.548J/g°C

Explanation:

Q = s × m × DeltaT

Q = Heat (J)

S = Specific Heat Capacity

M = mass (g)

DeltaT = Change in temperature (°C)

0.158Kg x 1000 = 158g

2.510J = s x 158g x (61°C-32°C)

2.510J/(158g x 29°C) = s

S = 0.54779.... J/g°C

S = 0.548 J/g°C

7 0
3 years ago
What coefficient is assumed if no coefficient <br> written before a formula in a chemical equation
Mice21 [21]

Answer:

1

Explanation:

Consider the following reaction:

Phosphorus burn in the presence of air and produced diphosphorus pentoxide.

Chemical equation:

P₄ + O₂ → P₂O₅

Balanced chemical equation:

P₄ + 5O₂ → 2P₂O₅

Equation is balanced because there are four phosphorus atoms ans ten oxygen atoms in both side of equation.

Coefficient with reactant and product:

P₄         1

O₂        5

P₂O₅    2

There is no coefficient written before P₄ it means only one P₄ is present.

7 0
4 years ago
4.14 Oxygen requirement for growth on glycerol Klebsiella aerogenes is produced from glycerol in aerobic culture with ammonia as
Iteru [2.4K]

Answer:

0.37 g

Explanation:

The molecular weight for Glycerol = 92

Number of Carbon atoms in glycerol (x)  C_3H_8O_3 = 3

Molecular weight of  the Biomass  ( Klebsiella aerogenes )

= CH_{1.73}O_{0.43}N_{0.24}

= \frac{23.97}{0.92}

= 26.1

From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as \delta _g) as follows:

= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)

= 4.15

Given that the yield of the Biomass = 0.40 g

However;

C = Yield of Biomass *\frac{Molecular weight of substrate}{Molecular weight of the Biomass}

C = 0.40*\frac{92}{26.1}

C = 1.41 g

Now , the oxygen requirement can be calculated as:

= \frac{1}{4}*(n*S -  C * \delta _{g})

= \frac{1}{4}(3*4.7-1.41*4.15)

= 2.1 g/mol

Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.

Now converting it to mass terms; we have:

= 2.1*\frac{number of mole of oxygen}{molecular weight of glycerol}

= 2.1 * \frac{16}{92}

= 0.3652 g

≅ 0.37 g

∴ The oxygen requirement for this culture in mass terms = 0.37 g

3 0
3 years ago
In the periodic table below, shade all the elements for which the neutral atom has a valence electron configuration of ns2np3 ,
Lorico [155]
Answer is: chemical elements<span> in </span>group 15<span> of the </span>periodic table have <span>neutral atom with a valence electron configuration of ns</span>²<span>np</span>³<span>.
</span>Nitrogen: [He] 2s² 2p³.
Phosphorus: [Ne] 3s² 3p³.
Arsenic: <span>[Ar] 3d</span>¹⁰ 4s² 4p³.
Bismuth: <span>[Xe] 4f</span>¹⁴ 5d¹⁰ 6s² 6p³.
Moscovium: predicted [Rn] 5f¹⁴<span> 6d</span>¹⁰<span> 7s</span>² 7p³.
These elements have 5 valence electrons.

5 0
4 years ago
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