Answer is x7 becuse i found it
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I think you will have t use theorem
Ba=Rv^2+vo^2
Ba=4^2+7^2
Ba=16+49
Ba=65
Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station
Answer:
x=$10
y=$12
Step-by-step explanation:
Step one:
given
let senior tickets be x
and child be y
8x+9y=188----1
also on the second day
x+5y=70-------2
the system of equation is
8x+9y=188-----1
x+5y=70---------2
x=70-5y, put this in 1
8(70-5y)+9y=188
560-40y+9y=188
-31y=-372
divide by -31
y=-372/-31
y=$12
put y= 12 in x+5y=70---------2
x+5(12)=70---------2
x+60=70
x=$10