If what you are trying to do is buy the most you can and still having some change left over then the answer would be 1 combo and 2 boxes of candy
Answer:
Step-by-step explanation:
Let q represent the number of quarters Theresa has. Then the value of her coins is ...
0.25q + 0.10(20 -q) = 2.75
0.15q = 0.75 . . . . . . . . . subtract 2.00, collect terms
q = 0.75/0.15 = 5
Theresa has 5 quarters and 15 dimes.
Slope: (y2-y1)/(x2-x1)
(0,7) and (-4,7)
(7-7)/(-4-0) = 0/ -4
The slope is 0
The domain is the x-axis and the range is the y-axis.
So the range of the function would be the Y values given.
So the range would be (3, 6, 9, 12, 15).
Distribute The 4 In Problem Number 2. (4*2.5X)+(4*1.25) = 77
Simplify. 10X+5 = 77. Now, Subtract 5 From Both Sides.
10X = 77-5
10X = 72.
Now, Divide.
X = 72/10.
X = 7.2.
For 13, We Have This:
3/5p+2/3 = 8.
Now, Subtract 2/3.
3/5p = 7 1/3
Now, Divide.
7 1/3 Needs To Be Converted To An Improper Fraction.
It Becomes 22/3.
22 5 110
--- * --- = ----
3 3 9
Now, Make Into A Proper Fraction.
It Becomes 12 And 2/9.
