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spin [16.1K]
2 years ago
9

If 11 1/2 inches of rope is being cut into 1 1/2 inch pieces, how many pieces of rope can be cut?

Mathematics
2 answers:
nordsb [41]2 years ago
8 0

Answer:

➡7pieces

Step-by-step explanation:

Let's suppose that x = the number of ropes that can be cut.

➡X = 11\frac{1}{2} ÷ 1\frac{1}{2}

➡X = 11.5 ÷ 11.5

➡X \approx 7.66

➡X = \bf 7pieces

uysha [10]2 years ago
6 0

Answer:

7 whole pieces

Step-by-step explanation:

There is 11.5 inches of rope.

Length of a piece = 1.5 inches

No . of pieces = total / unit length

= 11.5 / 1.5

= 7.667

There will be 7 whole pieces

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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

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Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

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Z = (x - mean)/standard deviation

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For x = 4171,  Z = (4171 - 3311)/860 = 1  

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Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

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Answer:

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A fair charges an admission fee of 2 dollars for each person. Let a be the cost of admission (in dollars) for P people. Write an
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