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jarptica [38.1K]
3 years ago
12

In experiment 6 we will perform a Fischer Esterification (Vollhardt, chapter 9-4 and 19-9). Suggest what could happen if you wer

e to attempt recrystallization of a carboxylic acid with ethanol or an ester with water.
Chemistry
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

Acid-Catalyzed Ester Hydrolysis

Explanation:

Fischer Esterification is a reversible reaction and the Le Châteliers principle can be used for the reaction to be completed. For the reverse reaction of Fischer Esterification, using the hydrolysis of ethyl ethanoate, the steps involved are:

1) An hydrogen ion is added to the ester and one of the lone pairs on the oxygen double-bonded to the carbon atom takes the hydrogen ion.

2) The lone pairs on the oxygen of a water molecule takes the positive charge on the carbon atom.

3) The hydrogen ion is transferred from one oxygen atom to another.

4) Then an ethanol molecule is released (one of the products).

5) Reaction with a water molecule releases hydrogen from the oxygen and the other product (ethanoic acid) is formed.

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Select all of the physical properties of matter
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Answer:

A) solubility

B)luster

D)Density

F)magnetism

Explanation:

A physical property is one that tells us everything about what a substance is when no change is is occurring to its constituent.

Such properties can be observed with our senses or instruments or pieces of apparatus.

  • Examples are luster, density, solubility, taste, odor, color, melting point, boiling point etc.
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3 years ago
0.450 kg of gasoline is spilled. If the ​density​ of gasoline is 0.665 g/mL, what ​volume​ of gasoline is spilled?
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0.276 kg

Explanation:

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3 years ago
Complete the sentence. The atomic number of an element is found by counting the number of _______ in an atom. A. isotopes B. ele
Kipish [7]
D.) Protons............
8 0
3 years ago
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Describe what subatomic particle is involved in light emission.
KiRa [710]

Answer:

Option C= light is emitted as electron falls from the excited state to the ground state releasing a photon.

Explanation:

Electrons are responsible for the production of colored light.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

How electrons produce the colored light:

Excitation:

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De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

8 0
4 years ago
You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with
ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in \frac{50.0}{22.4}=2.23 moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of N_2 react to give 2 mole of NH_3

So, 2.23 moles of N_2 react to give 2.23\times 2=4.46 moles of NH_3

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{4.46mole}{5.0L}

\text{Molarity}=0.89M

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0
3 years ago
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