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jarptica [38.1K]
3 years ago
12

In experiment 6 we will perform a Fischer Esterification (Vollhardt, chapter 9-4 and 19-9). Suggest what could happen if you wer

e to attempt recrystallization of a carboxylic acid with ethanol or an ester with water.
Chemistry
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

Acid-Catalyzed Ester Hydrolysis

Explanation:

Fischer Esterification is a reversible reaction and the Le Châteliers principle can be used for the reaction to be completed. For the reverse reaction of Fischer Esterification, using the hydrolysis of ethyl ethanoate, the steps involved are:

1) An hydrogen ion is added to the ester and one of the lone pairs on the oxygen double-bonded to the carbon atom takes the hydrogen ion.

2) The lone pairs on the oxygen of a water molecule takes the positive charge on the carbon atom.

3) The hydrogen ion is transferred from one oxygen atom to another.

4) Then an ethanol molecule is released (one of the products).

5) Reaction with a water molecule releases hydrogen from the oxygen and the other product (ethanoic acid) is formed.

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4 years ago
What is the pH of a solution that has a [H+] = 0.010 mol/L?
Serjik [45]

Answer:

pH = 2

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hope this helps :3

Download pdf
5 0
2 years ago
2. What was the primary reason in the 1850's driving the curiosity of atoms?
nalin [4]

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4 0
4 years ago
IF ANSWER I WILL GIVE BRAINLESS
vovikov84 [41]

Answer:

Answer 9 - 100 joules energy was at the producer level

Answer 10 - Remaining energy is used in metabolism

Explanation:

Answer 9

The energy at each trophic level is only 10% of the energy at its previous trophic level.

The energy at producer level is X

10 % of X = 10 Joules

\frac{10}{100} * X = 10\\X = 100Joules

Answer 10

Because the remaining 90% energy is utilized by the producer for its metabolism

3 0
3 years ago
Read the following chemical equations.
lora16 [44]

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻  ⇒2K⁺O⁻²H⁺ + I₂⁰

Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

Learn more:

  • (Redox reactions) brainly.com/question/13978139

8 0
3 years ago
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