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Airida [17]
2 years ago
9

A gas at STP has a volume of 1.00 L. If the pressure is doubled and the temperature remains constant, what is the news of the ga

s?
Chemistry
1 answer:
4vir4ik [10]2 years ago
3 0

Answer: PV = nRT

A gas at STP... This means that the temperature is 0°C and pressure is 1 atm.

R is the gas constant which is 0.08206 L*atm/(K*mol)

Rearranging for volume

V = nRT/P

The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)

PV = k

where k is a constant.

This means that

P₁V₁ = k = P₂V₂

P₁V₁ = P₂V₂

(1 atm) * (1 L) = (2 atm) * V₂

V₂ = 0.5 L

The new volume of the gas is 0.5 L.

Explanation:

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Answer:

84.2mL

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 128mL

Initial pressure (P1) = 500mmHg

Final pressure (P2) = stp = 760mmHg

Final volume (V2) =..?

Thus, the new volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

500 x 128 = 760 x V2

Divide both side by 760

V2 = (500 x 128)/760

V2 = 84.2mL

Therefore, the new volume of the gas is 84.2mL

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Hope this helps!

4 0
3 years ago
A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
tester [92]

Answer:

V₁  = 374.71  mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁  = 456 mL × 295 K / 359 k

V₁  = 134520 mL.K /  359 k

V₁  = 374.71  mL

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