Answer:
Explanation:
¡Hola!
En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:
Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):
Quiere decir que las moles de N2(g) que se agregaron son:
¡Saludos!
Answer:
- <em>A compound that conducts an electric current in aqueous solution or in the molten state is</em> a <u>ionic compound</u>.
Explanation:
Some examples of ionic compounds are NaCl, KF, KI, MgSO₄.
Ionic compounds are formed by positivie ions (named cations) and negative ions (named anions). The strong electrostatic atraction between cations and anions permits the formation of crystals, which are stuctures characterized by a regular pattern. In solid state the ions are in fixed positions.
In order to conduct electricity, the charged particles (cations and anions in the case of the ionic compounds) need to move freely.
Hence, since in solid state, ionic compounds do not conduct electric current. But, <em>in molten (liquid) state or in aqueous solution, ionic compounds conduct electric current because, then, the ions move freely.</em>
Answer:
Molecularity of the rate determining step = 2
Explanation:
Step 1 (slow): H₂O₂ + I⁻ -----> H₂O + OI⁻
Step 2 (fast): H₂O₂ + OI⁻ -----> H₂O + O₂ + I⁻
The rate determining step in a reaction mechanism is also considered as slowest step.
Slowest step is also considered its highest activation energy in energy profile diagram.
In this case intermediate (IO⁻) is formed.
Step 1 considered as a slowest step.
So, Rate = K [H₂O₂][I⁻]
Molecularity = 2
Answer:
1.4 × 10^-4.
Explanation:
C3H6O3 + H2O <======> C3H5O3^- + H3O^+ ------------------------------------------(1).
So, from the question above we are given the following parameters or data which is going to help in solving this particular Question/problem;
=>concentration of the solution of lactic acid (CH3CH(OH)C00H) = 0.1 M and pH = 2.44.
Therefore, the concentration of the hydrogen ion[H^+} can be determined from the pH formula given below;
pH = - log { H^+}.
2.44 = - log { H^+}.
Therefore, {H^+} = 0.0036 M.
From the equation (1) given above, we have that the ratio for the equilibrium reaction is 1 : 1 : 1 :1. Therefore, molarity of C3H5O3^- = 0.0036 M and the molarity of C3H6O3 =( 0.1 - 0.0036 M) = 0.0964 M at equilibrium.
Hence, ka = {C3H5O3^-} { H3O^+} /{C3H6O3} = ( 0.0036 M)^2 /(0.0964 M) = 1.4 × 10^-4.
