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Molodets [167]
3 years ago
15

Hydrogen gas and nitrogen gas are used to make ammonia (NH3). Calculate the rate of reaction if the concentration of hydrogen ch

anged from 0.74 M to 0.088 M over 65
seconds
Chemistry
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

(b) The change favors the reactants which has more gas molecules. ... Describe the effect of increasing the concentration of nitrogen gas or hydrogen gas inside the ... (c) The change causes an decrease in ammonia favoring the reactants. ... (c) Catalysts do not affect the equilibrium only the rate of reaction

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The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq
Pavlova-9 [17]

Answer : The molarity of I_3^- in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)

First we have to calculate the moles of Na_2S_2O_3.

\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}

\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of I_3^-.

From the balanced chemical reaction, we conclude that

As, 2 moles of S_2O_2^{-3} react with 1 mole of I_3^-

So, 0.007696 moles of S_2O_2^{-3} react with \frac{0.007696}{2}=0.003848 mole of I_3^-

The moles of I_3^- = 0.003848 mole

Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

Therefore, the molarity of I_3^- in the solution is, 0.128 M

8 0
3 years ago
Electronic configuration [Ne]3s2 3p6​
saw5 [17]
The answer is Argon! From Ne you go 2 3s level elements and then 6 3p level elements
8 0
3 years ago
Question 11 (3 points)
amm1812
A: gain 2 ions
B: +2
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6 0
3 years ago
Convert the following to Fahrenheit
jeka94

Explanation:

1. 50°F

2. 86°F

3.104°F

4. 98.6°F

5. 32°F

Here is the formula

T(°F) = T(°C) × 9/5 + 32

or

T(°F) = T(°C) × 1.8 + 32

Hope it helps...

4 0
3 years ago
Which would have a greater molar mass, carbon monoxide or carbon dioxide? why?
IceJOKER [234]

Answer:

Carbon dioxide has a greater molar mass.

Explanation:

This is because carbon dioxide has 2 oxygen atoms increaseing the molar mass and carbon monoxide has only 1.

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3 years ago
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