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VladimirAG [237]
3 years ago
11

¿Qué volumen ocuparán 12 g de hierro?

Chemistry
1 answer:
sasho [114]3 years ago
8 0

Answer:

        \large\boxed{\large\boxed{volume=1.5cm^3}}

Explanation:

Translation:

  • <em>What volume will 12g of iron occupy?</em>

<em></em>

<h2>Solution</h2>

<em />

<em>Iron</em> is a solid substance at room temperature. You can find the <em>volume</em> of solids (and of not solids) using the density.

      Density=\dfrac{mass}{volume}

You can obtaindthe density of most pure substances in the internet. The density of<em> iron</em> at room temperature is 7.874 g/cm³.

Thus, substituting in the formula, you get:

      7.874g/cm^3=\dfrac{12g}{volume}\\ \\ \\ volume=\dfrac{12g}{7.874g/cm^3}\\ \\ \\ volume=1.5cm^3

The answer is rounded to two significant figures because the input, 12g, has two significant figures.

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If It’s 960 Km/h, then it will take 1 hour to fly there.

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Judging by the electron domain geometry, which type of hybrid orbitals does this molecule have? s sp sp2 sp3
Aleksandr-060686 [28]
The molecule have TETRAHEDRAL HYBRID ORBITAL.
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3 years ago
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Please answer I need this to get a good grade. (;
zheka24 [161]

Answer:

94.74 mol NO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Using Dimensional Analysis
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

3714 L O₂ at STP

<u>Step 2: Identify Conversions</u>

RxN:   7 mol O₂ = 4 mol NO₂

STP:   22.4 L = 1 mol

<u>Step 3: Stoichiometry</u>

<u />3714 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2} )(\frac{4 \ mol \ NO_2}{7 \ mol \ O_2} ) = 94.7449 mol NO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

94.7449 mol NO₂ ≈ 94.74 mol NO₂

5 0
3 years ago
What does the group number plus number of bonds equal?
hjlf

Answer:

A stable compound with a complete octet or electronic configuration

Explanation:

The Periodic table is the arrangements of chemical elements in horizontal rows (called 'Periods') and vertical columns (called 'Groups') based on their various physical and chemical properties.

Elements in the same group have a common quality being that they have the same number of free (valent) electrons in their outermost shell. For example, elements in group 1 all have one valent electron in the outermost shell as compared to elements in group 5 which have five valent electrons in the outermost shell. Therefore the group number tells us the number of valence electrons of all the elements in that group.

Meanwhile, elements in the same period have the same number of outermost shell but an increasing number of valence electrons as one goes across the period from left to right.

Elements form chemical bonds in an effort to achieve chemical stability. Chemical stability is achieved when the shells of the elements are fully filled with electrons and achieved a stable electronic configuration of 2 or 8.

The type of bonds formed depend on the number of valence electrons available for bonding in the outermost shell of the element.

So the element Oxygen for example which has 6 valence electrons, in its outermost shell tends to form covalent bonds (a bond achieved by sharing electrons). It is easier for oxygen to form a covalent bond by sharing its valence electrons with another element than to lose all six valence electrons in order to achieve a stable octet state  

The element Chlorine (Cl, with seven valence electrons) on the other hand tends to form electrovalent or ionic bonds by accepting an electron from a metal element like Sodium (Na) to achieve a complete octet. It is easier for Cl to achieve a stable octet state by accepting an electron than losing all 7 valence electrons.

Therefore, the group number (an indicator of the number of valence electrons in the outermost shell) plus the number of bonds formed equals a stable atom or compound with a complete electronic configuration.

5 0
3 years ago
Which element could provide one atom to make an ionic bond with fluorine
Drupady [299]
Lithium i believe is the answer
8 0
3 years ago
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