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VladimirAG [237]
3 years ago
11

¿Qué volumen ocuparán 12 g de hierro?

Chemistry
1 answer:
sasho [114]3 years ago
8 0

Answer:

        \large\boxed{\large\boxed{volume=1.5cm^3}}

Explanation:

Translation:

  • <em>What volume will 12g of iron occupy?</em>

<em></em>

<h2>Solution</h2>

<em />

<em>Iron</em> is a solid substance at room temperature. You can find the <em>volume</em> of solids (and of not solids) using the density.

      Density=\dfrac{mass}{volume}

You can obtaindthe density of most pure substances in the internet. The density of<em> iron</em> at room temperature is 7.874 g/cm³.

Thus, substituting in the formula, you get:

      7.874g/cm^3=\dfrac{12g}{volume}\\ \\ \\ volume=\dfrac{12g}{7.874g/cm^3}\\ \\ \\ volume=1.5cm^3

The answer is rounded to two significant figures because the input, 12g, has two significant figures.

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8 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
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b. 16,00L

c. 12,31L

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Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

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25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

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<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
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