The first train leaves the station at 6:15 A.M The second train leaves at 6:55A.M How much later does the second train leave the
1 answer:
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Answer: 11.1 m
Step-by-step explanation:
This can be solved by the Pythagorean theorem where;
c² = a² + b²
c is the hypotenuse which is the distance from the top of the building to the tip of the shadow.
a is the height
c is the length
32² = 30² + b²
b² = 32² - 30²
b² = 1,024 - 900
b² = 124
b = √124
b = 11.1 m
The speed of the first car was 6 miles/hour
<h3>Further explanation</h3>Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem!
<u>Given:</u>
Distance between two cars = d = 10 miles
Time Taken = t = 1 hour
Distance covered by the first car = d₁ = 2 + d₂
<u>Unknown:</u>
Speed of the first car = v₁ = ?
<u>Solution:</u>
- Velocity of Runner : brainly.com/question/3813437
- Kinetic Energy : brainly.com/question/692781
- Acceleration : brainly.com/question/2283922
- The Speed of Car : brainly.com/question/568302
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle
