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lukranit [14]
2 years ago
9

Consider this reaction: NH4 HPO42− → NH3 H2PO4− Which is the Bronsted-Lowry acid ? NH4 HPO42- HPO42– H2PO4–.

Chemistry
1 answer:
kvv77 [185]2 years ago
8 0

Bronsted - Lowry acid in the given reaction is NH₄, as it gives H⁺ ion.

<h3>What is Bronsted - Lowry acid?</h3>

According to the theory of Bronsted - Lowry, acids are those substances which gives H⁺ ion or proton in the aqueous medium.

Given chemical reaction is :

NH₄ + HPO₄²⁻ → NH₃ + H₂PO₄⁻

In the above reaction NH₄ is the Bronsted - Lowry acid as it gives H⁺ ion in the reaction and changes to NH₃ which is the conjugate base of NH₄. Whereas HPO₄²⁻ is the  Bronsted - Lowry base as it accepts the H⁺ ion to form H₂PO₄⁻ which is the conjugate acid of it.

Hence, option (1) is correct, i.e. NH₄ is the Bronsted - Lowry acid.

To know more about Bronsted - Lowry acid, visit the below link:

brainly.com/question/1435076

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Explanation:

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3 years ago
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How many moles are equal to 89.23g of calcium oxide, CaO?
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1.59moles

Explanation:

Mass  of CaO = 89.23g

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Number of moles = ?

Solution:

The mole is a unit of measurement in chemistry used to delineate the number of particles an atom contains.

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Number of moles = \frac{mass}{molar mass}

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learn more:

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2 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
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Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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