<span> E = h v where v = frequency h = plancks constant 6.626 * 10 - 34
4.8 * 6.626 = 31.8 </span>
48.78%
Percentage of MgSO4 = mass of MgSO4/ mass of sample (MgSO4. 7H20) and multiply it by 100.
1) Excess reagent
1 mol N2 / 3 mol H2
6.0 mol N2 *3 mol H2 / 1 mol N2 = 18 mol H2
18mol H2 > 12 mol H2 => H2 is limiting (you need 18 mol H2 to use all the 6 mol N2), then N2 is in excees.
12.0 mol H2 * 1mol N2/ 3 mol H2 = 4 mol N2 is the quantity that will react, then the excess is 6 mol N2 - 4 mol N2 = 2 mol N2
2) NH3 produced
12 mol H2 * [2 mol NH3 / 3 mol H2] = 8 mol NH3
Aslso, 4 mol N2 *[2molNH3 / 1 molN2] = 8 mol NH3, the same result.
3) Yield
80% * 8 mol NH3 = 6.4 mol NH3
The correct answer is false. The statement given does not describe a property in general. However, it speaks of a specific type of property which is the physical property. This property is the one that does not change the identity of a substance. A property can also be a chemical property where the identity of a substance is changed.
<span>The formula actual yield /
theoretical yield is used to calculate the percent yield of a reaction.
This value is a measure of how much product is produced relative to the what is
supposed to be produced. It seems that the given in the problem is incomplete so we cannot really give a specific value. </span>
