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meriva
4 years ago
13

Which situation is the best example of interia

Chemistry
1 answer:
AveGali [126]4 years ago
6 0
One's body movement to the side when a car makes a sharp turn. Tightening of seat belts in a car when it stops quickly. A ball rolling down a hill will continue to roll unless friction or another force stops it.
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Calculate the number of molecules in 64.5 grams of nitrogen
Anuta_ua [19.1K]
The correct answer is D 4.29x10^24
6 0
3 years ago
Suppose you carry out a titration involving 3.00 molar HCl and an unknown concentration of KOH. To bring the reaction to its end
snow_tiger [21]

Answer: The concentration of the KOH solution is 1.01 M

Explanation:

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of HCl = 1

n_2 = acidity of KOH = 1

M_1 = concentration of HCl = 3.00 M

M_2 = concentration of KOH = ?

V_1 = volume of HCl = 35.3 ml

V_2 = volume of KOH = 105.0 ml

Putting the values we get:

1\times 3.00\times 35.3=1\times M_2\times 105.0

M_2=1.01

Thus the concentration of the KOH solution is 1.01 M

3 0
4 years ago
Determine the enthalpy change for the decomposition of calcium carbonate. CaCO₃(s) --> CaO(s) + CO₂(g) given the thermochemic
Hunter-Best [27]

Answer: c. 179 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Given:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O (l)   \Delta H_1= 65.2 kJ/mol     (1)

Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)    \Delta H_2= -113.8 kJ/mol   (2)

C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_3= -393.5 kJ/mol   (3)

2Ca(s)+O_2(g)\rightarrow 2CaO(s) \Delta H_4=-1270.2 kJ/mol    (4)

On subtracting eq (1) from eq (2) we have:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l) - Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

\Delta H=-113.8-(65.2)kJ/mol=-179kJ/mol

Hence the enthalpy change for the raection is 179.0 kJ/mol.

6 0
3 years ago
12.0 g NaHSO4 (MM: 120.1 g/mol) is dissolved in water to make a 2.00 L solution. What is the molarity of the resulting NaHSO4 so
dexar [7]

Answer:

0.05 M

Explanation:

First we <u>convert 12 g of NaHSO₄ into moles</u>, using the <em>given molar mass</em>:

  • 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄

We can now <u>calculate the molarity of the resulting solution</u>, using the <em>calculated number of moles and the given volume</em>:

  • Molarity = moles / liters
  • Molarity = 0.10 mol / 2.00 L = 0.05 M

5 0
3 years ago
Read 2 more answers
What happens when two sound waves meet in constructive interference?
vivado [14]

Answer:

D

Explanation:

The sound gets louder

8 0
3 years ago
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