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meriva
3 years ago
13

Which situation is the best example of interia

Chemistry
1 answer:
AveGali [126]3 years ago
6 0
One's body movement to the side when a car makes a sharp turn. Tightening of seat belts in a car when it stops quickly. A ball rolling down a hill will continue to roll unless friction or another force stops it.
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What is the answer to [h+]=0.235M
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What are you trying to work out???
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3 years ago
[Need this right now, how do I do this???]
VARVARA [1.3K]

If your collecting at STP, you can use the converting constant of 22.4 litters/ One Mole. So, you would have convert ml to L and then go from there.

Also, when working with grams, you usually need to know the gas your working with. As one mole equals the atomic mass of an element in grams.

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the table shows the types of elements that form two componds. which of the following statements is true about how the bonding oc
Grace [21]

Electrons are shared in compound X and transferred in compound Y.

<h3>Further explanation  </h3>

1. ionic bonding  

Bonding that occurs due to electron transfer. Can occur in metal and non-metal atoms. To get stability, atoms release or bind electrons to get stable electron regulation from noble gases  

2. covalent bonding  

Bonding that occurs due to shared use of electron pairs  

The two bound atoms contribute their electrons to produce bonds  

Generally occurs in non-metallic elements  

So compound X = covalent bond (metal with metal) and compound Y= ionic bond(metal with non metal)

  • Compound X : shared electron
  • Compund Y : transferred electron
3 0
3 years ago
Fill in the blanks i will mark brainlist and 20 points i need help asap plsss
gayaneshka [121]

Answer:

faster,  ocean, water,    Cooler,     less,     More,       Land.

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4 0
3 years ago
How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
Ivan

Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

6 0
2 years ago
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