The correct answer is D 4.29x10^24
Answer: The concentration of the KOH solution is 1.01 M
Explanation:
According to neutralization law:

where,
= basicity of
= 1
= acidity of KOH = 1
= concentration of HCl = 3.00 M
= concentration of KOH = ?
= volume of HCl = 35.3 ml
= volume of KOH = 105.0 ml
Putting the values we get:


Thus the concentration of the KOH solution is 1.01 M
Answer: c. 179 kJ/mol
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
Given:
(1)
(2)
(3)
(4)
On subtracting eq (1) from eq (2) we have:
- 


Hence the enthalpy change for the raection is 179.0 kJ/mol.
Answer:
0.05 M
Explanation:
First we <u>convert 12 g of NaHSO₄ into moles</u>, using the <em>given molar mass</em>:
- 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄
We can now <u>calculate the molarity of the resulting solution</u>, using the <em>calculated number of moles and the given volume</em>:
- Molarity = moles / liters
- Molarity = 0.10 mol / 2.00 L = 0.05 M