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Elza [17]
3 years ago
7

William has 8 1/4 cups of fruit juice.  If he divides the juice into 3/4 cup servings, how many servings will he have?

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

8 1/4 = 33/4

33/4 / 3/4 =

33/4 * 4/3 = 132/12

132/12 = 11

 he will have 11 servings


nikdorinn [45]3 years ago
7 0

Answer: 11 servings

Step-by-step explanation:

To get the number of servings, all we need to do is divide 8 1/4 by 3/4

converting 8 1/4 to improper fraction will yield 33/4

8 1/4 ÷ 3/4

=33/4 ÷ 3/4

= 33/4 ÷ 4/3

The 4 at the numerator will cancel the 4 at the denominator. we will be left with;

=33/3 =11

Therefore, there will be 11 servings.

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What number has 62 hundreds and 5 tens
fomenos

Answer:

6250

Step-by-step explanation:

Definition of the question

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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

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Therefore 23rd term of the sequence is 118.

4 0
3 years ago
At a recent baseball game, anyone under age 9 was given one free hotdog.
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Step-by-step explanation:

8 0
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I’m trying to prove this but I’m stuck... :( <br><br> Can someone help ?
Tom [10]
I can help, but what are you exactly trying to do here?
7 0
3 years ago
You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that \sigma = 12000

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

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1000\sqrt{n} = 1.96*12

Dividing both sides by 1000:

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(\sqrt{n})^2 = (1.96*12)^2

n = 553.2

Rounding up:

A sample size of 554 is needed.

5 0
3 years ago
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