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Arturiano [62]
3 years ago
14

Two point charges exert a 5.50 N force on each other. What will the force become if the distance between them is increased by a

factor of 10?
Physics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

0.055 N

Explanation:

From coulomb's law,

F α 1/r²

F = k/r²

F₁r₁² = F₂r₂²......................... Equation 1

Where F₁ = Initial force, r₁ = initial distance, F₂ = Final force, r₂ = Final distance.

making F₂ the subject of the equation

F₂ = F₁r₁²/r₂²..................... Equation 2

Given: F₁ = 5.50 N.

Let: r₁ = x m, then r₂= 10x m

Substitute into equation 2

F₂ = 5.5(x²)/(10x)²

F₂ = 5.5x²/100x²

F₂ = 5.5/100

F₂ = 0.055 N.

Hence the force becomes 0.055 N

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A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi
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the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

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The force that both satellites experience is:

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F2 = G M_e m2 / r²

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  • M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

<em>F1/F2 = 1/2</em>

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

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  • m2 is the mass of satellite 2
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Thus,

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F2c = m2 a2 r / r = m2 a2

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F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

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a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

<em>a1/a2 = 1</em>

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