Answer:
0.055 N
Explanation:
From coulomb's law,
F α 1/r²
F = k/r²
F₁r₁² = F₂r₂²......................... Equation 1
Where F₁ = Initial force, r₁ = initial distance, F₂ = Final force, r₂ = Final distance.
making F₂ the subject of the equation
F₂ = F₁r₁²/r₂²..................... Equation 2
Given: F₁ = 5.50 N.
Let: r₁ = x m, then r₂= 10x m
Substitute into equation 2
F₂ = 5.5(x²)/(10x)²
F₂ = 5.5x²/100x²
F₂ = 5.5/100
F₂ = 0.055 N.
Hence the force becomes 0.055 N