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pantera1 [17]
2 years ago
11

A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

rolleys stick together after collision, find the velocity that they of with move
​
Physics
1 answer:
Luda [366]2 years ago
6 0

Answer:

Approximately 0.29\; {\rm m \cdot s^{-1}}.

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass m and velocity v is p = m\, v.

The momentum of the two trolleys before the collision would be:

  • 4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}.
  • 3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}.

Thus, the total momentum of the two trolleys right before the collision would be 2\; {\rm kg \cdot m \cdot s^{-1}}.

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}.

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass m = 7\; {\rm kg} would continue to be v = 2\; {\rm kg \cdot m \cdot s^{-1}} shortly after the collision.

Rearrange the equation p = m\, v to find the velocity of the two trolleys combined:

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}.

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The frequency of the radio station is
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6 0
3 years ago
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Why to astronauts appear weightless while they are filmed performing activities inside the orbiting space shuttle?
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However, although they are constantly falling on the Earth, they do not fall because the ship orbits at a sufficient speed (in the same direction of rotation of the Earth) so that the centrifugal force is balanced with the Earth's gravitational pull.

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Answer:

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Object distance u = 12 cm

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Lens at a distance = 6.86 cm  (Approx)

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