Answer:
A.Glycogenesis: Glycogen synthase
B. Glucogenesis: Fructose 1,6 biphosphate phosphatase
C. Urea cycle : Carbamoyl phosphate synthetase
D.Fatty acid synthesis: Acetyl CoA carboxylase
E.Glycolysis : Phosphofructokinase 1
F. Pentose phosphate pathway: Glucose-6-phosphate dehydrogenase
Explanation:
A. Glycogen synthase converts glucose into glycogen during glycogenesis.
B. Fructose 1,6 biphosphate phosphatase catalyzes condensation of dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate during glucogenesis.
C. Carbamoyl phosphate synthetase I catalyses production of arbamoyl phosphate during urea cycle.
D. Carboxylase controls fatty acid metabolism.
E. The phosphofructokinase 1 is an important enzyme that regulate formation of two-phosphate sugar molecules during glycolysis.
F. Glucose-6-phosphate dehydrogenase participates in the pentose phosphate pathway. This pathway gives reducing energy to cells.
Answer:
Plate has all the essential nutrients that is required by the bacteria.
Explanation:
Bacteria grows on the plate, which indicates that the plate has all the essential nutrients that is required by the bacteria. Bacteria needs a type of media for its growth which contains all the necessary items which plays a key role in its growth and development. This plate has a media that contains food which the bacteria use for its growth and development so that's why we can say that plate has all the essential nutrients that is required by the bacteria.
Answer:
1:1
Explanation:
What is the concentration of H+ ions at a pH = 7?
⇒ 0.0000001 mol/L
What is the concentration of OH– ions at a pH = 7?
⇒ 0.0000001 mol/L
What is the ratio of H+ ions to OH– ions at a pH = 7?
1 :1
Answer:
The correct answer is option c. Haploid spores.
Explanation:
In the plants, spores are normally unicellular and haploid and produced by the process of meiosis in the sporophytic body of the plant.
These haploid spores undergo the mitotic division and develop a new individual called gametophyte that forms gametes eventually.
Thus, the correct answer is option C. Haploid spores.
The burden of diseases A and B in country Z is that disease B has a higher prevalence than
disease A. That is option D.
<h3>Health statistics of Country Z</h3>
Health statistics is used by professionals to summarize the health status or information on the health of individuals in a particular geographical location.
The basic statistic tools that can be used to check the health status of a population are,
The prevalence rate is the total number of cases of a disease existing in a population divided by the total population.
The prevalence rate of disease A = 225 per 100,000 population while the prevalence rate of disease B = 500 per 100,000 population.
Therefore, the burden of diseases A and B in country Z is that Disease B has a higher prevalence than
disease A.
Learn more about prevalence here:
brainly.com/question/25151633
