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Olenka [21]
3 years ago
14

Someone help me please

Mathematics
1 answer:
goblinko [34]3 years ago
5 0
C. X= 3/5 and D. X= 7/5
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Susan uses the function p(x) = 4x to determine the perimeter of a square when she knows the side length, x. Which statements are
mr_godi [17]

We are given the function p(x) = 4x for the perimeter of the square.

Where x represents the known side length of the square.

x is the independent variable and Perimeter P is the dependent variable on x.

<em>Because value of P total depends on the value of side length x of the square.</em>

Therefore, following statement are true about the given function:

<h3>The perimeter is the dependent variable.</h3><h3>The value of p(x) depends on the value of x.</h3><h3>The length of the side of the square is the independent variable.</h3>
7 0
4 years ago
cookie recipe calls for 1/4 teaspoon of vanilla extract she has 9/12 of a teaspoon in her kitchen how many batches of cookies ca
Andreas93 [3]
She can make 3

(9/12= 3/4)
7 0
4 years ago
Pls help what is Increase 5.4 by 1 1/27. <br><br>PLS HELP<br><br>T-T
tresset_1 [31]

Answer:

5/4

Step-by-step explanation:

1.2.3.4.5.6.7.8.9.10.11.12.13.14.15.16.17.18.19.2p

7 0
3 years ago
A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(
Verizon [17]
For this case we have the following function:
 f (t) = -16t2 + 48t + 100
 The average rate of change is:
 (f (t2) - f (t1)) / (t2 - t1)
 We have then:
 For t1 = 3:
 f (3) = -16 * (3) ^ 2 + 48 * (3) + 100
 f (3) = 100
 For t2 = 5:
 f (5) = -16 * (5) ^ 2 + 48 * (5) + 100
 f (5) = -60
 Substituting values:
 AVR = (-60 - 100) / (5 - 3)
 AVR = -80
 Answer:
 
The average rate of change of f (t) from t = 3 seconds to t = 5 seconds is -80 feet per second.
8 0
4 years ago
Determine the surface area of the triangle prism below
nasty-shy [4]

Answer:

Myself answers:

Step-by-step explanation:

The surface area of the triangle prism, although not drawn to scale can only be:

D. 4320 square feet

4 0
3 years ago
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