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Olenka [21]
3 years ago
14

Someone help me please

Mathematics
1 answer:
goblinko [34]3 years ago
5 0
C. X= 3/5 and D. X= 7/5
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Solve the inequality 12(1/2x-1/3)>8-2x
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Answer:8(1/2x - 1/4)> 12 - 2x

a.x > 7

b.x > 7/3

c.x > 5/3

d.x > 5/3

Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x

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3 years ago
Evaluate the spherical coordinate integral
expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1  ==>  <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4  ==>  <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2  ==>  -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5  ==>  -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3

Rewrite the integrand:

-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3

The integral is then

\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}

5 0
3 years ago
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