Answer:
Δe=0.578 kJ/kg
Explanation:
Given data
Velocity v₁=0 m/s
Velocity v₂=34 m/s
to find
Specific energy change Δe
Solution
The specific energy change is simply determined from change in velocity
Δe=(v₂²-v₁²)/2
Put the given values to find the specific energy change

Δe=0.578 kJ/kg
Answer:
The answer is C, a thermometer reads 0.1 degree higher than it should.
Answer:
30 points you say its only 5
Explanation:
LIAR