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iren2701 [21]
3 years ago
12

"The team wants to delete from Dataset A all activities related to users in Dataset B. How can an Einstein Consultant help them

achieve this_______?
Physics
1 answer:
lesantik [10]3 years ago
5 0

Adittional Information:

The Universal Containers company used Einstein Analytics to create two datasets:

Dataset A: contains a list of activities with an "activitylD" dimension and a "userlD" dimension

Dataset B: contains a list of users with a "userlD" dimension

Answer Choices:

A. Use the dataflow transformation "delete" and set "userlD" as the deletion ID.

B. Use a combination of dataflow transformations: "augment" and "filter."

C. Use an external ETL tool to extract both datasets and delete records.

D. Use the recipe operation "delete" and set "userlD" as the deletion ID.

B. Use a combination of dataflow transformations: "augment" and "filter."

Answer:

B. Use a combination of dataflow transformations: "augment" and "filter."

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A boat having stones floats in water. If stones are unloaded in water, what will happen to the level of water?​
Pani-rosa [81]

Explanation:

If the stones are unloaded from the boat, the weight of the boat will decrease. Therefore, the volume of the water displaced by the boat will also decrease. Due to this, the volume of the boat immersed in the water decreases. Hence, the level of the water around the boat will decrease.

5 0
3 years ago
If 5.7 grams of gold has 3 cubic centimeters than whats the density of gold in g/cm3
Aleonysh [2.5K]
Density: 1.9 g/cm3

density = mass/volume
d = 5.7/3
d = 1.9
3 0
3 years ago
A simple pendulum is 1.15 meters long and has a period of 6.29 seconds. The pendulum is on an unknown planet. What is the accele
Nastasia [14]

Answer:

The value of the acceleration of gravity of the Unknown Planet = 1.14 \frac{m}{s^{2} }

Explanation:

length of the pendulum (L)= 1.15 m

Time period (T)= 6.29 seconds

We know that time period  of a simple pendulum is given by

⇒ T = 2\pi × \sqrt\frac{L}{g}

put the values in the above formula we get

⇒ T = 2\pi × \sqrt \frac{1.15}{g}

⇒ 6.29 = 2\pi × \sqrt \frac{1.15}{g}

By solving the above equation we get

⇒ g = 1.14 \frac{m}{s^{2} }

This is the value of the acceleration of gravity of the Unknown Planet.

7 0
3 years ago
You have a graduated cylinder that you use to measure volume. The cylinder
ad-work [718]

Answer:

D. 21 ml

Explanation:

Since, the cylinder is marked and graduated in the intervals if 1 ml. Therefore, the values between two consecutive ml, such as between 30 ml and 31 ml can not be determined. Because, we do not have any scale in between the ml. So, the least count of this instrument is 1 ml. This graduated cylinder can give the answers to zero decimal places, accurately. And it can not determine any decimal value due to its graduating or the marking limitation. So, all the options given, contain a decimal value, except for the option D. In option D there is no decimal value, hence it is a correct answer.

D. <u>21 ml</u>

5 0
3 years ago
Read 2 more answers
The table below summarizes four situations (A, B, C, and D) in which a motorcycle has a given
serg [7]

Answer:

Explanation:

a = (vf - vi)/ t

A  a = (5 - 15) / 10 = - 1 m/s²

B  a = (25 - 30) / 15 = - 1/3 m/s²

C  a = (25 - 20) / 2 = 5/2 m/s²

D  a = (-15 - (-10)) / 3 = -5/3 m/s

from most negative to most positive

D, A, B, C

5 0
3 years ago
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