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Tcecarenko [31]
3 years ago
5

Pls quickkkkkkkkkkkkkk​

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0

Answer:

See below.

Step-by-step explanation:

i) A + B + C

= 4x² + y² - 6xy + 3y² + 12x² + 8xy + 6x² + 8y² + 6xy

= 24x² + 12y² + 8xy

ii) 2A + B - C

= 2(4x² + y² - 6xy) + 3y² + 12x² + 8xy - 6x² - 8y² - 6xy

= 8x² + 2y² - 12xy + 3y² + 12x² + 8xy - 6x² - 8y² - 6xy

= 14x² - 3y² - 10xy

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Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

^nP_r=\frac{n!}{(n-r)!}

For our given problem n=16 and r=4.

^{16}P_4=\frac{16!}{(16-4)!}

^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680

Therefore, 4 participants can be chosen in 43,680 different ways.  

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