Solve x2 − 7x + 12 = 0. x = −3, x = −4 x = 3, x = 4 x = 2, x = 6 x = −2, x = −6

Mathematics

1 answer:

UNO [17]2 years ago

6 0

Answer:

x=4, x=3

B is correct.

Step-by-step explanation:

Given: $x^2-7x+12=0$

Using middle term splitting factor the left side equation.

$x^2-4x-3x+12=0$

$(x-4)(x-3)=0$

Equate each factor to 0 and solve for x

x-4=0 or x-3=0

x=4 and x=3

Hence, The solution of the equation is 4 or 3

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Find the missing factor 4x^2+19x-5=(x+5)( )<br><br> NEED HELP PLEASE

S_A_V [24]

Answer:

4x^2+19x-5=(x+5)(4x -1)

Step-by-step explanation:

The given expression is 4x^2 + 19x - 5

The leading coefficient is 4 and last term is -5

Multiply them, we get -20

Now find the factors of -20 such that when you add the factors we have to get 19.

-1*20 = -20

20+ (-1) = 19

The right factors are -5 and 9.

4x^2 + 19x - 5 =4x^2 + 20x -1x - 5

= 4x(x + 5) -1(x + 5)

= (x + 5)(4x -1)

The missing factor is (4x -1)

Thank you.

4 0

3 years ago

Identify the horizontal

jonny [76]

Answer:

y=0

Step-by-step explanation:

Hello!

To solve this problem and find the asymptote you must find the value of x, for which F (x) (or y) becomes infinite, for this we solve the equation for X

$y=\frac{3}{5X} \\X=\frac{3}{5y}$

As you can see if Y takes a value of zero, then X would tend to be an infinitely large value so we conclude the horizontal asymptote is y = 0, I also attached the graph!