Firstly look at the options carefully and we will get to know that two answer options are incorrect because 2 of them are representing AT MOST SIGN which we don't need. So in that way Options B and D are eliminated.
So Now we are left with 2 options A and C. Lets figure it out.
We know that Carlos has 5 complete set with 4 individual figures and josh has 3 complete sets with 14 individual figures.
So lets write in the numerical language:-
let us assume that complete sets are X.
ATQ,
5x + 4 ≥ 3x + 14
subtracting 3x from both sides.
5x -3x + 4 ≥ 14
2x + 4 ≥ 14
subtracting 4 from both sides
2x ≥ 14 - 4
2x ≥ 10
dividing both sides by 2
x ≥ 5 Answer
So correct answer option is C
Here's the answer, using the quadratic formula
Answer:
uwuu
Step-by-step explanation:
ok the reason y iput uwu because uwu
A) area of square = base*height/////Triangle= 0.5*base*height
=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)
B) a^2+b^2=c^2 (pythagorean theorem)
((27^2/3)*(16^1/4))^2 + (27^1/3)*(16^3/4)
(9*2=(18^2))=324 + (3*8= 24^2)= 576
324+576= 900
(900)^1/2= 30
hypotenuse= 30
C)( a^2/3*b^1/2)= 36*2(two sides)= 72
(a^1/3b^3/4)=24
(a^2/3*b^1/4)= 18
72+24+18+30(hypotenuse)= 144=perimeter
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