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zzz [600]
2 years ago
5

Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.

Mathematics
1 answer:
8090 [49]2 years ago
6 0

Answer:

  (a)  -5

Step-by-step explanation:

The vertical scale factor for the graph and the function can be found by comparing the y-value of a point on f(x) to the y-value of a point on g(x). The graph conveniently marks two corresponding points with these y-values:

  f(-2) = 2

  g(-2) = -10

The value of k in g(x)=k·f(x) is the ratio of these y-values:

  k = g(-2)/f(-2) = -10/2 = -5

The value of the vertical scale factor k is -5.

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Deffense [45]
Y=20x-300

it's -300 because she pays 300 for her supplies and mower.
4 0
3 years ago
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On March​ 1, 2018, Mandy Services issued a​ 3% long-term notes payable for​ $15,000. It is payable over a​ 3-year term in​ $5,00
lord [1]

Answer:

amount of total cash payment is $5450

Step-by-step explanation:

Given data

amount = $15000

principal = $5000

rate = 3% = 0.03

to find out

the amount of total cash payment

solution

we know according to question is Each yearly installment will include both principal repayment of​ $5,000 and interest payment for the preceding​ one-year period

so first we calculate interest i.e.

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now we calculate the amount of total cash payment i.e.

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6 0
2 years ago
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Can you help me please
Leto [7]

2.5

Step-by-step explanation:

Multiply 2.5 by y and you get x

4 0
3 years ago
What is the domain of the function f(s)=7s +15? what is the range?
timama [110]

It's a linear function.

Domain of a linear function is the set of all real numbers.

If the slope of linear function is different than 0, then range is the set of all real numbers.

We have f(s) = 7s + 15. The slope = 7 ≠ 0. Therefore:

Answer: Domain=\mathbb{R};\ Range=\mathbb{R}

5 0
2 years ago
What is an equation of the line that passes through the point (-6,-4)(−6,−4) and is parallel to the line x+6y=12x+6y=12?
masya89 [10]

Answer:

x + 6y + 30 = 0

Step-by-step explanation:

x + 6y = 12

6y = -x + 12

y = -⅙x + 2

Slope: -⅙

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4 0
3 years ago
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