Answer:
1=x
Step-by-step explanation:
Answer:
a) 32
b) 
Step-by-step Explanation:
Initial pattern has 7 sticks.
Second one has 7+5 sticks.
Third has 7+5+5 sticks.
.
.
.
Sixth has 7+5+5+5+5+5=32 sticks.
$n^{th}$ has $7+ 5(n-1)$ sticks.
3y = -x + 3
y= (-1/3)x + 1
perpendicular: 3
y + 1 = 3(x - 6)
y + 1 = 3x - 18
y = 3x - 19
Answer:
0.4 , 0.1
Step-by-step explanation:
Let number of boys be = b , number of girls = b + 4 . As total students = 20 b + b + 4 = 20 → 2b + 4 = 20 → 2b = 20 - 4 = 16 → b = 16 / 2 = 8 (boys) , so girls = 12
Prob (a random first child is a boy) = boys / total students = 8 c 1 / 20 c1, or = 8 / 20 = 0.4
Prob ( a 'Tina' out of two Tina is the last) = 2 c 1 / 20 c 1 , or = 2 / 20 = 0.1
Given:
Current revenue = $6000
<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases
We are told to find f, when R(f) </span><span>< 6000
Since </span>R(f)= -100f^2+400f+6000
R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000
Subtract 6000 from both sides
-100f^2 + 400f + 6000 - 6000 < 6000 - 6000
-100f^2 + 400f < 0
⇒ 400f - 100f^2 < 0
Divide the equation by 100
400f/100 - 100f^2/100 < 0/100
4f - f^2 < 0
Add f^2 to both sides of the equation
4f - f^2 + f^2 < 0 + f^2
4f < f^2
Divide both sides by f
4f/f < (f^2)/f
4 < f
⇒ f > 4
⇒ f ≥ 5
Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
