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Leokris [45]
2 years ago
9

NO LINKS!! Please help me​

Mathematics
2 answers:
Wewaii [24]2 years ago
8 0

Answer:

A

Step-by-step explanation:

\cos(\theta)=\dfrac{\textsf{adjacent side}}{\textsf{hypotenuse}}=\dfrac{5}{13}

\textsf{As }\cos(\theta) > 0 \textsf{ the angle is in quadrant I or IV}

Using Pythagoras' Theorem a² + b² = c² to find the side opposite the angle:

⇒ 5² + b² = 13²

⇒ b² = 144

⇒ b = 12

⇒ opposite side = 12

\implies \sin(\theta)=\dfrac{\textsf{opposite side}}{\textsf{hypotenuse}}=\dfrac{12}{13}

\textsf{As }\sin(\theta) < 0 \textsf{ then }\sin(\theta)=-\dfrac{12}{13} \textsf{ and the angle is in either quadrant III or quadrant IV}

Therefore, the common quadrant is quadrant IV and

\sin(\theta)=-\dfrac{12}{13}

Tatiana [17]2 years ago
6 0

Answer:

A

Step-by-step explanation:

Since cosine is positive and sine is negative that puts θ in Quad IV.

From right triangles we know:

Cos θ = adjacent/hypotenuse = 5/13

sin θ = opposite/hypotenuse = ?/13

To find the opposite side across from θ use the pythagorean theorem.

5² + y² = 13²

25 + y² = 169

y² = 144

y = 12

we are given  that sin is < 0 so sinθ = -12/13

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