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Llana [10]
2 years ago
11

How can one fourth x − 3 = one half x + 8 be set up as a system of equations?

Mathematics
1 answer:
Ganezh [65]2 years ago
5 0
1/4x-3=1/2x+8
Then x=20.
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HELP RN PLEASEEE for a quiz
sattari [20]

Answer:

Step-by-step explanation:

( x_{1} , y_{1} )

( x_{2} , y_{2} )

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

parallel lines have the same slopes , perpendicular lines have slope which are opposite reciprocals.

~~~~~~~~~~~~~~~

A( 3 , 5 )

B( - 2 , 7 )

m_{AB} = \frac{7-5}{-2-3} = - \frac{2}{5}

C( 10 , 5 )

D( 6 , 15 )

m_{CD} = \frac{15-5}{6-10} = - \frac{5}{2}

The answer is (A) Neither

8 0
2 years ago
Ik this isnt part of math but I really need help with this question please answer as soon as possible im being timed on this tes
kvasek [131]

Answer:I believe it is D I’m taking the same test to

Step-by-step explanation:

4 0
3 years ago
En red socks and ten blue socks are all mixed up in a dresser drawer. The 20 socks are exactly alike except for their colour. Th
Gennadij [26K]

Answer:

3 socks

Step-by-step explanation:

Given that, there are 10 red socks and 10 blue socks which are mixed up in the dresser drawer.

The socks are identical except the color.

We need to find out, the minimum number of socks to be taken out from the dark room so that there is at least a pair of matching socks comes out of the drawer.

Let us consider the cases:

First Two socks pulled out of the drawer.

Case 1: Both are red or both are blue.

In this case, the matching pair is ready.

But there can be other case as well.

Case 2:

One red and one blue color taken out.

Now, when we pull the third, there will be either red or blue.

That will make a pair.

Therefore, to cover up all the cases and to be certain to get a matching pair out of the drawer, <em>at least 3 socks must be taken out</em>.

So, the answer is:

We need to take out at least 3 socks.

5 0
3 years ago
A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random
g100num [7]

Answer:

97.4% probability

Step-by-step explanation:

Since there is only two possible outcome of inspecting the catridge : either defective or not, we can solve the problem using the binomial probability distribution (approximated to normal).

To approximate the binomial probability to normal, we find the expected value and the standard deviation of the probability of exactly x sucesses on n repeated trials with p probability

Expected values E(X) = np

Standard deviation √V(X) = √np(1-p)

using the z-score formula (X - μ)/σ, we can solve normally distributed problem.

Where μ is the mean and σ is the standard deviation. The Z-score is is the measure of how much a sample is from the mean. The p-value associated with this z-score which is the probability that the value of the measure is smaller than X can be checked on the z-score table.

FOR THIS QUESTION,

a random sample of 200 cartridges is selected

n = 200

Therefore If there are more than 0.02 × 200 = 4 defective, the sample will be returned.

To determine the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05

μ = E(X)

= 0.05 × 200 = 10

σ = √V(X) = √np(1-p)

= √200 × 0.05 × 0.95

= 3.08

This probability is 1 subtracted by the pvalue of Z when X =4

Z = (X - μ)/σ

Z= (4 - 10)/3.08

Z = -1.95

Z = -1.95 has a P-value of 0.026 (on the z-score table)

This means that there is a 1 - 0.026 = 0.974

= 97.4% probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05.

6 0
3 years ago
Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the g
Bumek [7]
Your parallel equation would be y=-3x-32.
5 0
3 years ago
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