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aleksley [76]
2 years ago
10

Match these items.

Physics
1 answer:
stiks02 [169]2 years ago
4 0

Answer:

Match with A) Single fixed pulley, B) block & tackle, or C) single moveable pulley

changes the direction of effort; input is 1/2 the distance; or system of pulleys

Explanation:

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A neon lamp produces what kind of visible spectrum?
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Answer:

Discrete

Explanation:

There can be many kind of visible spectrum. Some of them are as follows :Infrared,  Continuous , Blackbody  and Discrete.

A neon lamp produces discrete kind of visible spectrum. In this type of spectrum, the spectrum consists of different colors. It means that the neon lamp is made up of different colors or individual frequencies.

Hence, a neon lamp produces discrete visible spectrum.

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3 years ago
What factors will increase the amount of energy by kinetic
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Gravitational energy is the potential energy associated with gravitational force. If an object falls from one point to another inside a gravitational field, the force of gravity will do positive work on the object and the gravitational potential.

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3 years ago
A ball of mass 24.1 g is attached to a cord of length 0.417 m and rotates in a vertical circle. What is the minimum speed the ba
Karo-lina-s [1.5K]

Answer:

<em>the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

<em></em>

Explanation:

In order to avoid slack, the centripetal force of the ball must equal its weight at the top of the circle. Therefore,

F_c = F_g

m v² / r = m g

v² = g r

v = √[g r]

v = √[(9.8 m/s²)(0.417 m)]

<em>v = 2.02 m/s </em>

Therefore,<em> the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

6 0
3 years ago
A track star in the broad jump goes into the jump at 12 m/s and launches himself at 20° above the horizontal. How long is he in
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Explanation:

It is given that,

Initial speed of the broad jump, u = 12 m/s

It is launched at an angle of 20 degrees above the horizontal. Let t is the time for which the track star i in the air before returning to Earth. The motion of the track star in the broad jump can be treat as the projectile motion. The time of flight of the projectile is given by :

t=\dfrac{2u\ sin\theta}{g}

Putting all the values in above equation as :

t=\dfrac{2\times 12\times \ sin(20)}{9.8}

t = 0.837 seconds

So, the time for which the track star is in air is 0.837 seconds. Hence, this is the required solution.

3 0
3 years ago
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