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Zigmanuir [339]
3 years ago
6

An object is lifted at constant speed a distance h above the surface of the Earth in a time t. The total potential energy gain o

f the object is equal to?
a. the average force
applied
b. the object’s total
weight
c. the total work
done on the object
d. the object’s
acceleration
Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0
B.the objects total weight
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Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.
velikii [3]

Answer:

V = \frac{V_0x}{d}

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

E= -\frac{\Delta V}{x} (1)

If we want to consider the change in Voltage with respect to the position then it would be,

E= -\frac{dV}{dx}

According to the information provided, the potential is V_0 and there is a distance d, therefore

E= -\frac{V_0}{d} (2)

Taking equation (1) we can clear V, to what we have,

\frac{dV}{dx} = -E

dV = -Edx

Integrating,

V= - \int Edx

Substituting (2)

V = -\int \frac{V_0}{d} dx

V = \frac{V_0x}{d}

Where x is the height from the grounded plate.

8 0
3 years ago
A particular uniform solid disk has a mass of 24.0 kg and a radius of 1.50 m. The disk is rotating about an axle passing through
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L = 81 Kg.m^2/s^2

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L = I * ω

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So, the angular momentum is:

L = 27 Kg.m^2* 3rad/s=81Kg.m^2/s^2

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4 years ago
Help will mark as brainliest ​
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Answer:

option no.(a)

Explanation:

is a correct answer.....

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