A. anything less than 3.0 magnitude on a richters scale usually can't be felt by humans but instruments can pick it up.
For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.
We can calculate the initial speed to reach 110 cm of height with the following equation:

Where:
: is the final speed = 0 (at the maximum height of 110 cm)
: is the initial speed =?
g: is the acceleration due to gravity = 9.81 m/s²
h: is the height = 110 cm = 1.10 m
Hence, the <u>initial velocity</u> is:

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.
You can see another example here: brainly.com/question/13359681?referrer=searchResults
I hope it helps you!
The correct answer for this problem is c
Answer:
Velocity of the ping pong ball must be = V2= 6,035.34m/s
Explanation:
M1= momentum of the bowling ball
m1 = mass of the bowling ball= 5.8kg
v1= velocity of the bowling ball= 1.59m/s
M2= momentum of the ping pong ball
m2= mass of the ping pong ball= 1.528 g/1000= 0.001528kg
v2= velocity of the ping pong ball
Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s
Momentum of the ping pong ball = M2= M1= m2v2
= 0.001528 *v2= 9.222
v2= 9.222/0.001528= 6,035.34 m/s
-- loud sounds
-- bright lights
-- strong radio signals
-- Slinkies that can pinch you painfully
-- a tsunami in the ocean
-- earthquakes above Richter 5 or 6