Answer:
![Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal](https://tex.z-dn.net/?f=%20Q%20%3D%20787%20gr%20%2A%201%20%5Cfrac%7Bcal%7D%7Bgr%20C%7D%20%2A%2837-75%29C%20%3D%20-29906%20cal)
So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:
![29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ](https://tex.z-dn.net/?f=%2029906%20cal%20%2A%5Cfrac%7B4.184%20J%7D%7B1%20cal%7D%2A%20%5Cfrac%7B1KJ%7D%7B1000%20J%7D%3D%20125.127%20KJ)
Explanation:
For this case we know the mass of the water given :
![m = 787 gr](https://tex.z-dn.net/?f=%20m%20%3D%20787%20gr)
And we know that the initial temperature for this water is
.
We want to cool this water to the human body temperature ![T_f = 37 C](https://tex.z-dn.net/?f=%20T_f%20%3D%2037%20C)
Since the temperatures given are not near to 0C (fusion point) or 100C (the boling point) we don't need to use latent heat, then the only heat involved for this case is the sensible heat given by:
![Q= m c_p \Delta T](https://tex.z-dn.net/?f=%20Q%3D%20m%20c_p%20%5CDelta%20T)
Where
represent the specific heat for the water and this value from tables we know that
for the water.
So then we have everything in order to replace into the formula of sensible heat and we got:
![Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal](https://tex.z-dn.net/?f=%20Q%20%3D%20787%20gr%20%2A%201%20%5Cfrac%7Bcal%7D%7Bgr%20C%7D%20%2A%2837-75%29C%20%3D%20-29906%20cal)
So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:
![29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ](https://tex.z-dn.net/?f=%2029906%20cal%20%2A%5Cfrac%7B4.184%20J%7D%7B1%20cal%7D%2A%20%5Cfrac%7B1KJ%7D%7B1000%20J%7D%3D%20125.127%20KJ)
Answer:
A. Gamma decay
Explanation:
A form of nuclear decay in which the atomic number is unchanged is a gamma decay.
The atom has undergone a gamma decay.
In a gamma decay, no changes occur to the mass and atomic number of the substance.
- Gamma rays have zero atomic and mass numbers.
- When they cause decay, they cause no change to the mass and atomic numbers.
- They simply produce gamma rays during such reactions and these rays are very energetic.
Answer:
Ф = 239.73 rad
Explanation:
α = 12 + 15×t
W = ∫α×dt
= ∫(12 + 5×t)×dt
= 12×t + 2.5×t^2
then:
Ф = ∫W×dt
= ∫(12×t + 2.5×t^2)dt
= 6×t^2 + 5/6×t^3
therefore the angle at t = 4.88s is:
Ф = 6×(4.88)^2 + 5/6×(4.88)^3
= 239.73 rad
Answer:
8 mph
Explanation:
4 miles in half hour so you add 4 more for the second half
The average speed is 20.8 m/s
Explanation:
The average speed for the trip is given by:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
d is the distance covered
t is the time elapsed
For the trip in this problem, we have:
d = 187 km = 187,000 m is the distance travelled
The initial time is 10:00 pm while the arriving time is 12:30 am: this means that the time elapsed is 2.5 hours. Converting into seconds,
![t = 2.5 h \cdot (60)(60)=9000 s](https://tex.z-dn.net/?f=t%20%3D%202.5%20h%20%5Ccdot%20%2860%29%2860%29%3D9000%20s)
Therefore, the average speed for the trip is
![v=\frac{187,000}{9000}=20.8 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B187%2C000%7D%7B9000%7D%3D20.8%20m%2Fs)
Learn more about average speed:
brainly.com/question/8893949
brainly.com/question/5063905
#LearnwithBrainly