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3 years ago

List down all the functional groups that present in Levocabastine molecule.

Chemistry

1 answer:

AlladinOne [14]3 years ago

3 0

Answer:

Nitrile, amide, carboxylic acid, phenyl (aka. arene)

**There are so many functional groups, so I may list some you don't know. There may also be some that I am not aware of. However, these are all the ones I can see.**

Explanation:

Nitrile: (bottom-left) N triple bonded to C

Amide: (middle) N single bonded to 3 carbons

Carboxylic Acid: (bottom-right) C-CO2H

Phenyl: (top-right) six carbon ring with alternating double bonds

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3 years ago

At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.

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Explanation:

The given data is as follows.

T = 298 K, $\Delta H^{o}$ = -5645 kJ/mol

$\Delta G^{o}$ = -5798 kJ/mol

Relation between $\Delta H$ and $\Delta G$ are as follows.

$\Delta G^{o}$ = $\Delta H^{o} - T \Delta S^{o}$

-5798 kJ/mol = -5645 kJ/mol - $298 \times \Delta S^{o}$

-153 kJ/mol = - $298 \times \Delta S^{o}$

$\Delta S^{o}$ = 0.513 kJ/mol K

Now, temperature is $37^{o}C$ = (37 + 273) K = 310 K

Since, $\Delta G$ = $\Delta H^{o} - T \Delta S^{o}$

= $-5645 kJ/mol - 310 K \times 0.513 kJ/mol K$

= (-5645 kJ/mol - 159.03 kJ/mol)

= -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

$\Delta G = \Delta G_{310 K} - \Delta G_{298 K}$

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3 years ago

If this same quantity of energy were transferred to 2.5 kg of water at it's boiling point what fraction of the water would be va

garik1379 [7]

Answer:

Fraction of water that can be vaporized = 0.0961 or 9.61%

Note : The question is incomplete. The complete question is given below:

A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body.

If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what fraction of the water would be vaporized?

Explanation:

Energy released by a serving of Cheeze-Its = 130 kcal

Since 1 kcal = 4.18 kJ, 130 kcal = 130 * 4.18 kJ = 543.4 kJ

Heat of vaporization (evaporating or condensing) Hv, of water = 2260 J/g

From formula, quantity of heat, Q = mass * heat of vaporization

mass of water = 2.5 kg = 2500 g

Q = 2500 g * 2260 J/g

Q = 5650000 J = 5650 kJ

Therefore 2.5 kg of water requires 5650 kJ of heat for complete vaporization

Fraction of water that can be vaporized by 543.4 kJ energy = 543.4/5650

Fraction of water that can be vaporized = 0.0961 or 9.61%

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4 years ago

List down all the functional groups that present in Levocabastine molecule.​

List down all the functional groups that present in Levocabastine molecule.