The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
D milk turning sour
the other options are physical changes
ºC = K - 273
ºC = 96 - 273
= -177ºC
answer A
hope this helps!
Put the <em>wood and excess oxygen in a closed contai</em>ner that contains some device that can create a spark (to start the reaction).
Determine the <em>mass of container + contents</em>.
<em>Start the reaction</em> and, after everything has cooled down, again determine the <em>mass of container + contents</em>.
If the two masses are the same, you have demonstrated that the reaction obeys the Law of Conservation of Mass.