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Elza [17]
3 years ago
5

Express the following answers with the correct number of significant figures. 3.582 ÷ 0.0131

Chemistry
1 answer:
kkurt [141]3 years ago
7 0
Answer is 273

explanation:

The rule of division for significant figures is to put the answer to the least amount of significant figures presented in the problem.
0.0131 only has 3 sig figs which is 131
3.582 has 4 sig figs
The least amount is 3 in the problem
When you originally divide 3.582 and 0.0131 you get 273.4531 in your calculator

Now put it to 3 sig figs
4 is not greater than 5 so you don't need to round
273 is 3 sig figs.
So answer is 273
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Explain what helps convert non-rich oxygen blood cells back to oxygen rich cells?
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Answer:

As blood travels through the body, oxygen is used up, and the blood becomes oxygen poor. Oxygen-poor blood returns from the body to the heart through the superior vena cava (SVC) and inferior vena cava (IVC), the two main veins that bring blood back to the heart.

Explanation:

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1. What is the oxidation number for the silver ion in tarnish?
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Tarnish is Ag2S-silver sulfide and the oxidation state of silver is +1
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An indicator helps us to see the _____ during a titration experiment by causing a color change
Liula [17]

Answer:

Point of neutralization.

Explanation:

Indicators are used in titration experiments to show when the solution's pH is changing. For instance, a common indicator, phenolphthalein, turns pink in basic solutions, while it remains colorless in acidic solutions. The solution would turn a very light shade of pink when the pH reached above 7.

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3 years ago
A certain organ pipe, open at both ends, produces a fundamental frequency of 272 HzHz in air. Part A If the pipe is filled with
vladimir2022 [97]

Answer:

fundamental frequency in helium = 729.8 Hz

Explanation:

Fundamental frequency of an ope tube/pipe = v/2L

where v is velocity of sound in air = 340 m/s; λ is wave length of wave = 2L ; L  is length of  the pipe

To find the length of the pipe,

frequency  = velocity of sound / 2L

272 = 340 / 2 L

L = 0.625 m

If the pipe is filled with helium at the same temperature, the velocity of sound will change as well as the frequency of note produced since velocity is directly proportional to frequency of sound.

Also, the velocity of sound is inversely proportional to  square root of molar mass of gas; v ∝ 1/√m

v₁/v₂ = √m₂/m₁

v₁ = velocity of sound in air, v₂ = velocity of sound in helium, m₁ = molar mass of air, m₂ = molar mass of helium

340 / v = √4 / 28.8

v₂ = 340 / 0. 3727

v₂  =  912.26  m /s  

fundamental frequency in helium  = v₂ / 2L

fundamental frequency in helium = 912.26 / (2 x 0.625)

fundamental frequency in helium = 729.8 Hz

7 0
3 years ago
Reynolds number E. What is the mean velocity u. (ft/s) and the Reynolds number Re = pu., D/ for 35 gpm (gallons per minute) of w
Novay_Z [31]

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\  u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\    u=156\,in/s=13\,ft/s

The Reynolds number now can be calculated for this flow as

Re=\frac{\rho*u*D}{\mu}

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

<em>Viscosity</em>

\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}

<em>Diameter</em>

D=1.05in*(\frac{1ft}{12in} )=0.0875ft

Then the Reynolds number is

Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583

8 0
3 years ago
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