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puteri [66]
2 years ago
12

Using the bond energy values in the previous question, which molecule

Chemistry
1 answer:
oksano4ka [1.4K]2 years ago
5 0

Hydrogen molecule is a molecule that releases the most energy when forming its bonds as compared to other molecules.

<h3>What bond needs more energy?</h3>

We know that H-H bond energy is 432 kJ mol-1, CI - CI bond energy is 239kJ mol-1 and Br-Br bond energy is 193 kJ mol-1 so from this data we can conclude that more energy is required to break the bond between hydrogen atom.

Learn more about bond here: brainly.com/question/25596583

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pochemuha

Answer:

Br2+ 2H2O + SO2= 2HBr + H2SO4

Let's Compare the left side of the equation to the right side of the equation.

Left: Br= 2, H= 2, S= 1, O = 1+2

Right: Br=1, H= 1+2, S=1, O= 4

We can see that only S is balanced and not the other 3 elements.

I'll try to make each element balance.

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For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.

For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.

6 0
3 years ago
In terms of their electron configurations, why is cesium more likely to lose its valence electron than potassium?
Harlamova29_29 [7]

Explanation:

use the term electron sheilding, the more electrons between the valence el3ctron and nucleus the easier to lose the valence electron (more sheilding = easier to lose)

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