From the change in free energy, we can calculate the equilibrium constant by the equation <span>ΔG°=-RT ln(K) where K is the equilibrium constant.
-418.6x10^2 = -(8.314)(298) ln (K)
K = 2.38x10^73
K is expressed as:
K = 1 / Pso2 (Po2)^0.5 = 1/ </span>Pso2 (0.21)^0.5
2.38x10^73 = 1/ Pso2 (0.21)^0.5
Pso2 = 9.17x10^-74 atm
Explanation:
1kg x 0,37=370gHCL
370g/36,5g/mol=10,137mol/kg
1l=1,185kg
10,137 x 1,185kg/l =12,0mol/l
(x/ml(12mol HCL)*12mol/L)/100ml=0,025mol/L
x=
A precipitate will be formed through the double displacement method in chemical reactions. The chemical equation would be:
Na2CO3 + AgNO3 ----> NaNO3 + Ag2CO3.
Balancing would result to:
<span>Na2CO3 + 2AgNO3 ----> 2NaNO3 (aq)+ Ag2CO3.
</span>
Ag2CO3 is the precipitate formed. It is yellow in color but due to the presence of elemental silver, it is a bit grayish.