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nexus9112 [7]
3 years ago
13

Write the NET IONIC EQUATION between zinc and hydrochloric acid.

Chemistry
1 answer:
makkiz [27]3 years ago
6 0

Answer:

Zn_{(s)}+2H^{+}_{(aq)}\rightarrow Zn^{2+}_{(aq)}+H_2_{(g)}

Explanation:

Zinc reacts with hydrochloric acid to given zinc chloride and hydrogen gas. The liberation of the hydrogen gas can be confirmed by burning the gas. If the gas burns with pop sound, it means it is hydrogen gas

The molecular chemical equation for the reaction is:

Zn_{(s)}+2HCl_{(aq)}\rightarrow ZnCl_2_{(aq)}+H_2_{(g)}

The total ionic equation is:

Zn_{(s)}+2H^{+}_{(aq)}+2Cl^{-}_{(aq)}\rightarrow Zn^{2+}_{(aq)}+2Cl^{-}_{(aq)}+H_2_{(g)}

The net ionic equation is:

Zn_{(s)}+2H^{+}_{(aq)}\rightarrow Zn^{2+}_{(aq)}+H_2_{(g)}

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The atomic number of aluminum is 13. What is the correct designation of the electron configuration of aluminum?.
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2 years ago
How much heat, in calories, is needed to raise the temperature of 125.0 g of Lead (c lead = 0.130 J/g°C) from 17.5°C to 41.1°C?
pav-90 [236]
95.6 cal
are needed.
Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.
8 0
3 years ago
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