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yarga [219]
3 years ago
5

Find the slope of the line that passes through the given points (2,-7), (1,4)

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

Slope “m” = 1

Hence, the slope of the required line is 1.

Step-by-step explanation:

7/2+ -4/1 = 3/3 which is a whole number

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A car dealership advertises a used Toyota Tercel for only $400 down and $170 per month for 4 years. What is the total cost of th
erica [24]

Answer:

the answer is wrong!!  is 8,560 total cost

Step-by-step explanation:

170x48(4 years) = 8,160

8,160+400(down) = 8,560 total cost

7 0
4 years ago
What is the answer to the question 25% of what is 21?
g100num [7]
If we call the number "x" then:
x*25%=21
x*25/100=21
x=21*4
x=84

Hope this helps. :)
8 0
3 years ago
Read 2 more answers
The score on an exam from a certain MAT 112 class, X, is normally distributed with μ=78.1 and σ=10.8.
salantis [7]

a) X

b) 0.1539

c) 0.1539

d) 0.6922

Step-by-step explanation:

a)

In this problem, the score on the exam is normally distributed with the following parameters:

\mu=78.1 (mean)

\sigma = 10.8 (standard deviation)

We call X the name of the variable (the score obtained in the exam).

Therefore, the event "a student obtains a score less than 67.1) means that the variable X has a value less than 67.1. Mathematically, this means that we are asking for:

X

And the probability for this to occur can be written as:

p(X

b)

To find the probability of X to be less than 67.1, we have to calculate the area under the standardized normal distribution (so, with mean 0 and standard deviation 1) between z=-\infty and z=Z, where Z is the z-score corresponding to X = 67.1 on the s tandardized normal distribution.

The z-score corresponding to 67.1 is:

Z=\frac{67.1-\mu}{\sigma}=\frac{67.1-78.1}{10.8}=-1.02

Therefore, the probability that X < 67.1 is equal to the probability that z < -1.02 on the standardized normal distribution:

p(X

And by looking at the z-score tables, we find that this probability is:

p(z

And so,

p(X

c)

Here we want to find the probability that a randomly chosen score is greater than 89.1, so

p(X>89.1)

First of all, we have to calculate the z-score corresponding to this value of X, which is:

Z=\frac{89.1-\mu}{\sigma}=\frac{89.1-78.1}{10.8}=1.02

Then we notice that the z-score tables give only the area on the left of the values on the left of the mean (0), so we have to use the following symmetry property:

p(z>1.02) =p(z

Because the normal distribution is symmetric.

But from part b) we know that

p(z

Therefore:

p(X>89.1)=p(z>1.02)=0.1539

d)

Here we want to find the probability that the randomly chosen score is between 67.1 and 89.1, which can be written as

p(67.1

Or also as

p(67.1

Since the overall probability under the whole distribution must be 1.

From part b) and c) we know that:

p(X

p(X>89.1)=0.1539

Therefore, here we find immediately than:

p(67.1

7 0
4 years ago
Help please. I did my best to find the answer but...
lorasvet [3.4K]

Answer:

24

Step-by-step explanation:

This a special right triangle with angle measures of 30° 60° 90°

The side length that sees angle measure 30° is represented with a, the one that sees 90° is represented by 2a and the one that sees 60° is represented by a√2

AC sees angle B which has an angle measure of 60

(6√2)×(√2) = 24

4 0
3 years ago
Tell which value of the variable, if any, is a solution to the equation.
kvasek [131]

Answer:

14

Step-by-step explanation:

14+9=25

4 0
3 years ago
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