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3 years ago

8

What is the value of X?

2 answers:

horrorfan [7]3 years ago

4 0

You have to find out the solution first.

amid [387]3 years ago

4 0

2(x + 10) = 3x - 30

2x + 20 = 3x - 30

20 + 30 = 3x - 2x

50 = x

Answer is 50

You might be interested in

Rosie is a real estate agent and is paid the following for commission on sales: 4% for the first $50,000, 2% for the next $100,0

Elena-2011 [213]

Answer:

22,000

Step-by-step explanation:

4%/100=0.04

0.04*50,000=20,000 || 130,000-50,000=80,000 ||

2%/100=0.02

0.02*100,000= 2,000 || 80,000 - 100,000 ||

To explain it simply, Rosie receives 20,000 in commission for the first 50,000 of the sale. However, she sold a property for 130,000 meaning she also receives 2,000 for the next 100,000. Therefore she receives $22,000 in total on her $130,000 sale.

6 0

4 years ago

5/10+13/100 <br> what is the value of the expression

cluponka [151]

Answer:

63/100

Step-by-step explanation:

6 0

3 years ago

X-Y-2Z =-11<br> X-2Y-Z = -11 <br> -X+Y+3Z = 14

Snowcat [4.5K]

9514 1404 393

Answer:

(X, Y, Z) = (-2, 3, 3)

Step-by-step explanation:

We can subtract the second equation from the first to get ...

Y -Z = 0

We can add the third equation to the first to get ...

Z = 3

Then ...

Y -3 = 0 ⇒ Y = 3

and ...

X -3 -2(3) = -11

X = -2 . . . . . . . . . add 9

The solution is ...

(X, Y, Z) = (-2, 3, 3)

7 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbold%7B%20Find%5C%3A%20the%20%5C%3Avalue%5C%3A%20of%5C%3A%20x%3A%7D" id="TexFormula1" title

Andrews [41]

Answer:

hope this helps you!!!

Step-by-step explanation:

MARK AS BRAINLIEST!!

8 0

3 years ago

Read 2 more answers