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3 years ago

When converting between two measurement units, how can you tell which operation to use

Mathematics

2 answers:

german3 years ago

7 0

Most of the time its juss common sense where you can point the right measurement with just sense i guess

Jet001 [13]3 years ago

3 0

You just have to remember
Meters is times or divide by 100
Centimeters is divide or times by 10 (I think)
Millimeters is divide or times by 10
And so on
Because I don't think there is another way to tell
Sorry

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Which type of debt is often unsecured?

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Answer: mortgage

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3 years ago

Solve the following similar fraction. 3/4 + 1/4=?

borishaifa [10]

Answer:

4/4 or 1

Step-by-step explanation:

3/4 (75%) and 1/4 (25%) add them up and you get 1, (100%) or 4/4.

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3 years ago

HELP!! 50 POINTS!!!

aalyn [17]

Step-by-step explanation:

We have been given a table, which represents the projected value of two different houses for three years.

Part A:

$\text{Increase in value of house 1 after one year}=294,580-286,000$

$\text{Increase in value of house 1 after one year}=8580$

$\text{Increase in value of house 1 after two years}=303,417.40-294,580$

$\text{Increase in value of house 1 after two years}=8837.4$

We can see from our given table that the value of house 1 is not increasing at a constant rate, while a linear function has a constant rate of change, therefore, an exponential function can be used to describe the value of the house 1 after a fixed number of years.

$\text{Increase in value of house 2 after one year}=295,000-286,000$

$\text{Increase in value of house 2 after one year}=9,000$

$\text{Increase in value of house 2 after two years}=304,000-295,000$

$\text{Increase in value of house 2 after two years}=9,000$

We can see from our given table that the value of house 2 is increasing at a constant rat that is $9,000 per year. Since a linear function has a constant rate of change, therefore, a linear function can be used to describe the value of the house 2 after a fixed number of years.

Part B:

Let x be the number of years after Dominique bought the house 1.

Since value of house 1 is increasing exponentially, so let us find increase percent of value of house 1.

$\text{Increase }\%=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100$

$\text{Increase }\%=\frac{294,580-286,000}{286,000}\times 100$

$\text{Increase }\%=\frac{8580}{286,000}\times 100$

$\text{Increase }\%=0.03\times 100$

$\text{Increase }\%=3$

$\text{Increase }\%=\frac{303,417.40-294,580}{294,580}\times 100$

$\text{Increase }\%=\frac{8837.4}{294,580}\times 100$

$\text{Increase }\%=0.03\times 100$

$\text{Increase }\%=3$

Therefore, the growth rate of house 1's value is 3%.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For growth b is in form (1+r), where, r is rate in decimal form.

$3\%=\frac{3}{100}=0.03$

Upon substituting our values in exponential function form we will get,

$f(x)=286,000(1+0.03)^x$ , where, f(x) represents the value of the house 1, in dollars, after x years.

Therefore, the function $f(x)=286,000(1.03)^x$ represents the value of house 1 after x years.

Let x be the number of years after Dominique bought the house 2.

We can see that when Dominique bought house 2 it has a value of $286,000. This means that at x equals 0 value of house will be $286,000 and it will be our y-intercept.

Since value of house 2 is increasing 9000 per year, therefore, slope of our line be 9000.

Upon substituting these values in slope-intercept form of equation $(y=mx+b)$ we will get,

$f(x)=9000x+286,000$ , where, f(x) represents the value of the house 2, in dollars, after x years.

Therefore, the function $f(x)=9000x+286,000$ represents the value of house 2 after x years.

Part C:

Since values in exponential function increases faster than linear function, so the value of house 1 will be greater than value of house 2.

Let us find the value of house 1 and house 2 by substituting x=25 in our both functions.

$f(25)=286,000(1.03)^{25}$

$f(25)=286,000*2.0937779296542148$

$f(25)=598820.48788$

We can see that value of house 1 after 25 years will be approx $598,820.48.

$f(25)=9000*25+286,000$

$f(25)=225,000+286,000$

$f(25)=511,000$

We can see that value of house 2 after 25 years will be approx $511,000.

Since $511,000 is less than $598820.48, therefore, value of house 1 is greater than value of house 2.

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3 years ago

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3 years ago

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