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natka813 [3]
2 years ago
10

If tan (θ )=0.532 , and α is the complement of θ , then tan (α) =

Mathematics
1 answer:
goblinko [34]2 years ago
6 0

Answer:

tan(α) = 89.468

Step-by-step explanation:

90 - 0.532

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I need help im lost on finding n
shepuryov [24]

Answer:

If I read this right

3 (n -12) + 14 = 4 (7 - 5n)

First, remove the parentheses

3 n - 36 + 14 = 28 - 20 n

Combining terms

23 n = 28 - 14 + 36 = 50

n = 50 / 23 = 2 4/23 = 2.17

7 0
2 years ago
Read 2 more answers
Yvonne had a rope that measured 2/5 long. She
yawa3891 [41]

Answer:

Number of smaller ropes she can make from the larger rope = 2/3

Step-by-step explanation:

Total length of rope = 2/5 ft

Length of smaller rope = 3/5 ft

How many smaller ropes can she make from the larger rope?

Number of smaller ropes she can make from the larger rope = Total length of rope / Length of smaller rope

= 2/5 ÷ 3/5

= 2/5 × 5/3

= (2*5)/(5*3)

= 10/15

= 2/3

Number of smaller ropes she can make from the larger rope = 2/3

7 0
3 years ago
4 Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket salesfor
Kitty [74]
$10.50a + $3.75b = $2,071.50 It is given that b = 82 Therefore - $10.50a + ($3.75)(82) = $2,071.50 or $10.50a + $307.50 = $2,071.50 $10.50a = $2,071.50 - $307.50 = $1,764.00 Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
4 0
2 years ago
Read 2 more answers
Is (1, 2) a solution of 6x-y > 3?
nikdorinn [45]

Answer:

yes

Step-by-step explanation:

6(1)-2>3

6-2>3

4>3

3 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
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