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AfilCa [17]
2 years ago
9

A machine that drills holes for wells drilled to a depth of

Mathematics
1 answer:
s2008m [1.1K]2 years ago
5 0

Answer:

depth of -117 feet

Step-by-step explanation:

24 hours 72 feet, so one hour 72/24 = 3 feet

after 15 hours, another 3*15 = 45 feet, so the depth become 72 + 45 = 117 feet

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31 gallons of gas cost $82.15. What is the unit rate for 1 gallon of gas ?
alexgriva [62]
Divide total price by gallons:

82.15 / 31 = 2.65 for 1 gallon
7 0
3 years ago
How many 1/2 foot pieces can be cut from 6 foot ribbon?
MatroZZZ [7]
Number of ribbons that can be cut = 6 ÷ 1/2 
Number of ribbons that can be cut = 6 x 2/1
Number of ribbons that can be cut = 12 

 -----------------------------------------------------------------------------------------
Answer: 12  1/2 foot pieces can be cut from 6 feet ribbon
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8 0
3 years ago
Determine the range of the function $f(x) = -4x^2-8x-6$. Enter your answer in interval notation.
saveliy_v [14]

Answer:[tex]y=-4x^2 -8x-6

Step-by-step explanation:

6 0
3 years ago
Which graph represents a function with direct variation?
Elena L [17]

Answer:

Second graph with straight diagonal lines

Step-by-step explanation:

The second graph with straight diagonal lines represents the direct variation

The X and Y axis represents two variables A and B  and these two variables in case of second graph with straight lines are directly proportional to each other.

Hence, If value of variable A increases, then value of variable B will also increase

5 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
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