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Oduvanchick [21]
3 years ago
15

A researcher is 95% confident that the interval from 5.2 hours to 7.8 hours captures u = the true mean amount of time

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0
<h3>Answer: Choice B</h3>

No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.

====================================================

Explanation:

The greek letter mu is the population mean. It has the symbol \mu which looks like the letter 'u' but with a tail at the front or left side.

The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8

We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2

Since mu = 5 is not in the interval, it's not a plausible value for the population mean.

Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.

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Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec
Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

C. 0.010 < P-value < 0.025

b. Power of test = 1- β=0.2066

c. So the sample size is 88

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test

Here n= 7 and significance level ∝= 0.005

Critical value for a right tailed test with 6 df is 1.9432

Sample Standard deviation = s= 32

Sample size= n= 7

Sample Mean =x`= 630

Degrees of freedom = df = n-1= 7-1= 6

The test statistic used here is

Z = x- x`/ s/√n

Z= 630-600 / 32 / √7

Z= 2.4797= 2.48

P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For  a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

hypothesis mean = 600

standard deviation= 32

power = β=0.9

Z∝= 1.645

Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n=  ((1.645+1.282) 32/ 10)²

Putting the values  and solving we get 87.69

So the sample size is 88

5 0
3 years ago
pls helpppp c=30m+50 and c=20m+100. solve for c and show your work.
Contact [7]

Answer:c=200

Step-by-step explanation:

30(5) + 50 = 200

20(5) + 100 = 200

-------------------------------|

100 30m

- 50 - 20m

——— ———

50 10m 50/10 = 5 [m=5]

7 0
3 years ago
Simplify 30x-140-(x-4)
balu736 [363]

Answer:

x = 4.7

Step-by-step explanation:

30x - 140 -(x - 4)

Multiply the -1 into (x - 4)

30x - 140 - x + 4

Add/subtract

29x - 136 = 0

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29x = 136

\frac{29x}{29} = \frac{136}{29}

x = 4.689655172413793

8 0
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Answer:

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Step-by-step explanation:

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