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Oduvanchick [21]
2 years ago
15

A researcher is 95% confident that the interval from 5.2 hours to 7.8 hours captures u = the true mean amount of time

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
8 0
<h3>Answer: Choice B</h3>

No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.

====================================================

Explanation:

The greek letter mu is the population mean. It has the symbol \mu which looks like the letter 'u' but with a tail at the front or left side.

The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8

We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2

Since mu = 5 is not in the interval, it's not a plausible value for the population mean.

Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.

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Since zero has no value, it does not need to be included when writing a number in expanded form.

Step-by-step explanation:

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Step-by-step explanation:

domain is all ur x values.....

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Anna bought 8 tetras and 2 rainbow fish for her aquarium. The rainbow fish cost​ $6 more than the tetras. She paid a total of​ $
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Answer:

C, D, and E

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5 0
3 years ago
Read 2 more answers
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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LenaWriter [7]

Answer:

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Step-by-step explanation:

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