A rectangles side is 7.6 cm. the bottom of the rectangle is 11cm. what is the area?
2 answers:
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We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>
To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting from both sides of the equation
<u>This would give:</u>
f + -
= 6 -
f = 6 -
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>
To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)
Answer:
The probability that they will teach different courses is .
Step-by-step explanation:
Sample space is a set of all possible outcomes of an experiment.
In this case we will write the sample space in the form (x, y).
Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.
Denote every course by their first letter.
The sample space is as follows:
S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}
The outcomes where the the instructors will teach different courses are:
s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}
The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.
Compute the probability that they will teach different courses as follows:
Thus, the probability that they will teach different courses is .