Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
Answer:
D,x < 36 and x > 0, negative number cannot be in sq.root
Answer:
The cost has been reduced by approximately 33%.
Step-by-step explanation:
1% of 120 is 1.2.
80 divided by 1.2 is 66.66666666...
Meaning that $80 is about 66% of the original cost. Therefore, about 33% of the cost was removed.
Hope this helps
120 + 32x < = 720....with x being the number of seats
32x < = 720 - 120
32x < = 600
x < = 600 / 32
x < = 18.75
