Answer:
1. A container of milk 2L
2. An Eyedropper has 1 mL
3. A cup of punch 250 mL
4. A jar of pickles 500mL
Step-by-step explanation:
Without even measuring, just think of this problem logically. Remember that a 1 L is 1000mL, so it is 1000 times more than 1 mL.
A milk container would hold more than a cup of milk and that is more than 20 mL. The most logical answer would be 2L.
An eyedropper can hold just a little amount of liquid. Just think that it dispenses liquid in drops, the best answer would be 1mL (which is actually an estimate of the volume of a drop is.)
A cup of punch is about 250 mL. The keyword there is a CUP and 25L is a big amount and the cup would have to be HUGE.
Same as above, the keyword there is a jar. A 50L jar would be a very big amount for just a jar of pickles.
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
Answer:
The last one (-1,5)
Step-by-step explanation:
From (0,0), the R coordinate is one to the left meaning the x is negative and five up which means the y is positive 5 so... (-1,5) is the new location of R.
Answer:
The answer to 3/4x-1/6 is -0.126
Detailed Answers:
Volume of a Sphere (V) = 4/3 πr^3
1. Diameter (d) = 21.6 cm
Radius (r) = 21.6/2 = 10.8 cm
Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (10.8)^3
= 4/3 * 22/7 * 1259.712
= 88/21 * 1259.712
=> 5278.79
Volume (V) = 5278.79 cm^3
2. Diameter (d) = 16 cm
Radius (r) = 16/2 = 8 cm
Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (8)^3
= 4/3 * 22/7 * 512
= 88/21 * 512
=> 2145.52
Volume (V) = 2145.52 cm^3
3. Diameter (d) = 24 cm
Radius (r) = 24/2 = 12 cm
Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (12)^3
= 4/3 * 22/7 * 1728
= 88/21 * 1728
=> 7241.14
Volume (V) = 7241.14 cm^3
4. Diameter (d) = 6 cm
Radius (r) = 6/2 = 3 cm
Therefore,
= 4/3 πr^3
= 4/3 * 22/7 * (3)^3
= 4/3 * 22/7 * 27
= 88/21 * 27
=> 113.14
Volume (V) = 113.14 cm^3
