All categories

3 years ago

Round the sum of 40.88 and 16.6 to the nearest tenth

Mathematics

2 answers:

klasskru [66]3 years ago

7 0

Your will round the sum to 57.5

pantera1 [17]3 years ago

3 0

I'm assuming you don't want the numbers to be rounded until after they're added soooo:

40.88 + 16.6 = 57.48

After rounding to the nearest tenth : 57.5

You might be interested in

PLEASE HELP FAST ITS DUE SOONNN

Rudik [331]

Answer:

ST = CHORD

PR = RADIUS

MN = DIAMETER

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Y=? cm A15 B.10 C.3 D.5

Gelneren [198K]

What is the question?

3 0

3 years ago

Read 2 more answers

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

Mean of the integers 8,-11,18,-8,-3

g100num [7]

Answer:0.8, just add up and find the mean

8 0

3 years ago

Read 2 more answers

A car servicing station is running a special offer. The breakdown of the cost for different services is given below.

ohaa [14]

Answer:

C. It is the total cost of the membership fee and the tire pressure check for 12 months.

Step-by-step explanation:

The constant represents the sum of costs that are not "per car." Those are only "membership fee" ($50) and "tire pressure check" ($15/mo × 12 mo = $180).

3 0

3 years ago

Read 2 more answers