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yKpoI14uk [10]
2 years ago
13

Claire is a salesperson who sells computers at an electronics store. She makes a base pay of $80 each day and then is paid a $20

commission for every computer sale she makes. Write an equation for P,P, in terms of x,x, representing Claire's total pay on a day on which she sells xx computers.
Mathematics
1 answer:
Bezzdna [24]2 years ago
5 0
The answer is P= 20x+80
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(4x) to the power of -4​
Eva8 [605]

Answer:

3.90625×10^_03

Step-by-step explanation:

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4 0
3 years ago
Write the cosine ratio of angle b<br> and show work please
Dennis_Churaev [7]
The formula for cosine is adj/hyp. For angle B, 10 is the adjacent and 24 is the opposite. The hypotenuse ( in this case, 26) is the longest side. the ratio for angle b would be 10/26.

7 0
3 years ago
Simplify 4+(9×2)÷(4-2)+1
kogti [31]

First we have to work out everything inside the parentheses (according to PEMDAS):

9 × 2 = 18

4 - 2 = 2

Now, we can rewrite the expression:

4 + 18 ÷ 2 + 1

According to PEMDAS, we should complete the division in the middle first:

18 ÷ 2 = 9

Now we can rewrite the expression again:

4 + 9 + 1

And now it's as simple as just adding the three numbers together:

4 + 9 + 1 = 14


Your final answer is 14. :)

3 0
3 years ago
Read 2 more answers
Pyramid A is a right square pyramid with a height of 100 m and a square base with a perimeter of 356 m. Pyramid B has a square b
Tomtit [17]

Answer:

The volume of pyramid B is 3.5 times greater than the volume of pyramid A

Step-by-step explanation:

The area of squared based a pyramid is given by:

Area = \frac{1}{3}*s*s*h

Where 's' the length of the side of the base and 'h' is the height.

For pyramid A:

h= 100 m

s= 356/4 = 89 m

Area_A = \frac{1}{3}*89*89*100\\Area_A=264,033.33\ m^3

For pyramid B:

h= 215 m

s= 456/4 = 114 m

Area_B = \frac{1}{3}*114*114*215\\Area_B=931,380\ m^3

Pyramid B has a greater volume and the ratio between volumes is:

\frac{Area_B}{Area_A} =\frac{931,380}{264,033.33}\\\frac{Area_B}{Area_A} =3.5

3 0
3 years ago
-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4​
umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0
2 years ago
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