1 year ago

Find y so that (1/4) ^-3 × (4)^8 = (1/4)^ -4y.. help me please. I will mark brainliest

Mathematics

1 answer:

creativ13 [48]1 year ago

7 0

please mark me as brainlest

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$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

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$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

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Find y so that (1/4) ^-3 × (4)^8 = (1/4)^ -4y​.. help me please. I will mark brainliest

Find y so that (1/4) ^-3 × (4)^8 = (1/4)^ -4y.. help me please. I will mark brainliest