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VLD [36.1K]
3 years ago
14

Write the situation for the relationship "y = 2x - 5."

Mathematics
1 answer:
kompoz [17]3 years ago
3 0
Its letter b can u please help me in my question
You might be interested in
The sum of the measures of the angles in a triangle is 1800. If two of the angles are 72 and 76 degrees, what is the missing ang
ehidna [41]

Answer:

32

Step-by-step explanation:

72 + 76 = 148

180 - 148 = 32

I hope this helps!!

4 0
2 years ago
No links <br> 10pts<br> for answer 1 variables or values for answer 2 do not satisfy or satisfy
gulaghasi [49]

Answer:

hello

Step-by-step explanation:

6 0
2 years ago
What are the sizes of angles a, b, c and d? ​
Lilit [14]

Answer:

a = 26°

b = 48°

c = 26°

d = 106°

Step-by-step explanation:

c +  {154}^{o}  =  {180}^{o}  \\ c =  {180}^{o}  -  {154}^{o}  \\ c =  {26}^{o}

a = c (Alternate angles)

a =  {26}^{o}

b =  {48}^{o}

Corresponding angles

(a + d) + b = 180° (Interior angles)

{26}^{o}  + d +  {48}^{o}  =  {180}^{o}  \\ d +  {74}^{o}  =  {180}^{o}  \\ d =  {180}^{o}  -  {74}^{o}  \\ d =  {106}^{o}

8 0
2 years ago
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
Which of the values is equivalent to 5^–3? A) 1/15 B) 1/125 C) − 15 D) − 125
bazaltina [42]

Answer:

C 1/125

Step-by-step explanation:

5  ^−3

Calculate 5 to the power of −3 and get  

1/125

​

​

7 0
2 years ago
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