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kakasveta [241]
3 years ago
5

Which statement is true about acceleration?

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
The answer is C is think
You might be interested in
What is the gravitational force between two trucks, each with a masof 2.0x10^4 k
eduard

Answer:

6.67\cdot 10^{-3} N

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the two masses

r is the separation between the two masses

In this problem, we have

m_1 = m_2 = 2.0 \cdot 10^4 kg the mass of each truck

r = 2.0 m is their separation

Substituting,

F=(6.67\cdot 10^{-11}) \frac{(2.0\cdot 10^4 kg)^2}{(2.0 m)^2}=6.67\cdot 10^{-3} N

7 0
4 years ago
A ship maneuvers to within 2.50 x 10^3 m of an islands 1.80 x 10^3 m high mountain peak and fires a projectile at an enemy ship
Neporo4naja [7]

Answer:

Explanation:

Distance between ship and enemy ship

= 500 + 610

= 3110 m

Range of projectile

R = u² sin2θ / g

= (250x 250 sin 150) / 9.8

= 3188m

The projectile falls within a distance of 3188 - 3110 = 78 m from enemy ship

Height of mountain = 1800 m

We shall find the height of projectile when its horizontal displacement is 2500m

x = 2500 , y = ?

u = 2500 ,

y = x / cos θ - .5 g x² /u²cos² θ

\frac{2500}{.2588} - \frac{.5 \times9.8\times2500\times2500}{250\times250\times.2588}

9660 - 7315 m

= 2345 m

It is within 545 m from mountain peak .

8 0
3 years ago
How safe is Wind Energy? Use in your own words.
Kisachek [45]

Answer:

wind energy is safe

Explanation:

because it just is

5 0
3 years ago
Read 2 more answers
A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student
storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

m_1u_1+m_2u_2=(m_1+m_2)v

where the mass of the student m_1 is 48.5 kg,

the mass of the skateboard m_2 is m_2 kg,

the initial speed of the student u_1 is 4.25 m/s; and

the speed of the student and skateboard  v is 4.05 m/s.

So substituting the given values in the above formula to get:

(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05

206.125=196.425+4.05m_2

206.125 - 196.425 = 4.05m_2

m_2=\frac{9.7}{4.05}

m_2=2.39

Therefore, the mass of the skateboard is 2.39 kg.

7 0
3 years ago
A 40kg-skier starts at the top of a 12-meter high slope. At the bottom, she is traveling 10 m/s. How much energy does she lose t
KIM [24]
Energy at top = U = mgh = 40 * 9.8 * 12 = 4704 J

Energy at bottom = 1/2 mv² = 1/2 * 40 * 10² = 4000 / 2 = 2000 J

Energy Lost = Final - Initial = 4704 - 2000 = 2704 J

In short, Your Answer would be Option D

Hope this helps!
4 0
4 years ago
Read 2 more answers
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