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kakasveta [241]
3 years ago
5

Which statement is true about acceleration?

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
The answer is C is think
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A 3.0-kilogram cart possesses 96 joules of kinetic<br> energy. Calculate the speed of the car.
Dvinal [7]

Answer:

8.0 m/s

Explanation:

KE = ½ mv²

96 J = ½ (3.0 kg) v²

v = 8.0 m/s

5 0
3 years ago
3.accuracy is gauged by comparing the measured value of a known standard to its true value. assuming the mass of the water repre
tangare [24]

The glassware with the highest degree of accuracy is 250 mL beaker.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Accuracy compares the experimental value to the theoretical value.

Accepted density of water = 0.99 g/mL

1. 10 mL cylinder

Mass of water = 6.76 g

Volume of water = 6.8 mL

Density = mass /Volume

density = 6.76/6.8 = 0.99412 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99412 - 0.99 / 0.99 ] x 100

% error = 0.416 %

2. 50 mL cylinder

Mass of water = 24 g

Volume of water = 24.2 mL

density = 24/24.2 = 0.9917 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9917 - 0.99 / 0.99 ] x 100

% error = 0.172 %

3. 25 mL cylinder

Mass of water = 17 g

Volume of water = 17.1 mL

density = 17/17.1 = 0.99415 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99415 - 0.99 / 0.99 ] x 100

% error = 0.419 %

4. 250 mL beaker

Mass of water = 35 g

Volume of water = 35.3 mL

density = 35/35.3 = 0.9915 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9915 - 0.99 / 0.99 ] x 100

% error = 0.152 %

Lesser the percentage error, higher is the accuracy.

Thus, 250 mL beaker has the highest degree of accuracy.

Learn more about accuracy.

brainly.com/question/13099041

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4 0
2 years ago
What force causes centripetal acceleration of a car making a turn on a flat road?
Stella [2.4K]

The force that causes centripetal acceleration of a car making a turn on a flat road is friction

The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.

Fc = f

m v² / r = μ N

Fc ∝ 1 / r

The larger the centripetal force the the smaller the radius of curvature.

Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction

To know more about centripetal force

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3 0
1 year ago
A steel ball is whirled on the end of a chain in a horizontal circle of radius R with a constant period T. If the radius of the
CaHeK987 [17]

Answer:

<em>The centripetal acceleration will be increased to 1.33 of its initial state. </em>

Explanation:

<h3>Centripetal acceleration</h3>

The Centripetal acceleration of  an object is the acceleration of the object along a circular path  moving towards the center of the circular path. The centripetal acceleration is represented in the equation bellow

a_{c}  = \frac{V^{2} }{r} ...................................... 1

where a_{c} is the centripetal acceleration  

          v is the tangential velocity

          and r is the radius.

<h3>How the Change of Radius Affects the Centripetal Acceleration</h3>

Reference to equation 1 the centripetal acceleration ( a_{c}) is inversely proportional (y = \frac{k}{x}) to the radius of the circle or path. this means that when the radius increases the centripetal acceleration reduces and when the radius reduces the centripetal acceleration increases. The radius was reduced to 0.75R in the question that will amount to 1.33a_{c} increase in the centripetal acceleration. This can be obtained by multiplying the centripetal acceleration by the inverse of 0.75 which is 1.33.

Therefore, when the radius is reduced by 0.75R , the centripetal acceleration of the steel ball will increase by 1.33a_{c}. since the period is kept constant

4 0
3 years ago
A basketball was thrown and reached a velocity of 3 m/s in 0.5 seconds. What was the acceleration of the basketball?
Alborosie

Answer: acceleration is 6 m/s²

Explanation: V = vo + at. If initial speed Is zero,

V = at and a= V/t = 3m/s /0.5 s

6 0
3 years ago
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