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3 years ago

Distance travelled/time taken gives?

Physics

2 answers:

skad [1K]3 years ago

6 0

Answer:

speed

Explanation:

Speed = distance travelled/time taken

avanturin [10]3 years ago

6 0

Answer: Speed

Explanation:

Speed is defined as the rate of change of the position of an object in a direction. The speed of an object is calculated as the distance travelled divided by the time that is taken.

Speed is regarded as a scalar quantity since it has only direction but doesn't have magnitude. The answer to the above question is speed.

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Consider the following equilibrium at 979 K for the dissociation of molecular iodine into atoms of iodine. I2(g) equilibrium rea

GenaCL600 [577]

Answer: $I_2$ = 0.0050 M

$I$ = 0.0155 M

Explanation:

Initial moles of $I_2$ = 0.072 mole

Volume of container = 3.9 L

Initial concentration of $I_2=\frac{moles}{volume}=\frac{0.072moles}{3.9L}=0.018M$

The given balanced equilibrium reaction is,

$I_2(g)\rightleftharpoons 2I(g)$

Initial conc. 0.018 M 0

At eqm. conc. (0.018-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[I]^2}{[I_2]}$

$K_c=\frac{(2x)^2}{0.2-x}$

we are given : $K_c=1.60\times 10^{-3}$

Now put all the given values in this expression, we get :

$1.60\times 10^{-3}=\frac{(2x)^2}{(0.018-x)}$

$x=0.0025$

So, the concentrations for the components at equilibrium are:

$[I]=2\times x=2\times 0.0025=0.0050$

$[I_2]=0.018-x=0.018-0.0025=0.0155$

Hence, concentrations of $I_2$ and $I$ are 0.0050 M ad 0.0155 M respectively.

4 0

3 years ago

In order to do work, the force vector must be

aliina [53]

in the same direction as the displacement vector and the motion

5 0

3 years ago

The space shuttle releases a satellite into a circular orbit 630 km above the Earth.

solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

$\displaystyle g=\frac{GM}{r^2}$

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}$

Remove units to make the equation easier to read.

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Multiply the numerator out.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Add the terms in the denominator.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}$

Simplify this equation.

$\displaystyle g=8.11045189 \ \frac{m}{s^2}$

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

$\displaystyle a = \frac{v^2}{r}$

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.